Well if the ship was in space their shouldn’t be a loud bang. Because you can’t hear anything in space
Answer:
Q = 1057.5 [cal]
Explanation:
In order to solve this problem, we must use the following equation of thermal energy.
where:
Q = heat energy [cal]
Cp = specific heat = 0.47 [cal/g*°C]
T_final = final temperature = 32 [°C]
T_initial = initial temperature = 27 [°C]
m = mass of the substance = 450 [g]
Now replacing:
![Q=450*0.47*(32-27)\\Q=1057.5[cal]](https://tex.z-dn.net/?f=Q%3D450%2A0.47%2A%2832-27%29%5C%5CQ%3D1057.5%5Bcal%5D)
You did not provide the options. However, the options are
I = 6.0, R= 4.0 ohms
I = 9.0, R= 2.0ohms
I = 3.0, R= 2.0ohms
I = 8.0, R= 8.0 ohms
Answer:
The order of the resistors from the highest to the lowest is:
I = 8.0, R= 8.0 ohms
I = 6.0, R= 4.0 ohms
I = 9.0, R= 2.0ohms
I = 3.0, R= 2.0 ohms
Explanation:
ohm's law states that voltage across a conductor is directly proportional to the current flowing through it. V = IR
Based on this formula, the voltages in each of the resistors are calculated below from the highest to the lowest
V = 8 * 8 =64 volts
V = 6 * 4 =24 volts
V = 9 * 2 =18 volts
V = 3 * 2 =6 volts
This can be solve using the formula P = I^2 * Rwhere P is the powerI is the CurrentR is the resistanceP = I^2 * R
1/4 Watt = I^2 * 100 ohm solve for II^2 = 1/400 I = 0.05 amps then using the formula to solve for the voltage:V = I * RV = 0.05 amps * 100 ohms V = 5 volts
The air that is inside a ship is much less dense than water. That's what keeps it floating! ... The closer the total density of the ship is to the density of the same volume of water, the greater the amount of the ship that will be in the water.
