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2 years ago

What is the metric unit of weight? Gram/pound/Newton/milliliter

1 answer:

7 0

Weight is force.
The metric unit of force is the Newton.
1 Newton is the force needed to accelerate 1 kilogram at the rate of 1 m/s² .

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^^ help :c

ipn [44]

I need help to I have a test and I need help to

6 0

3 years ago

A 5 kilograms bowling ball is dropped out a window. It hits the ground, and bounces upward. The velocity change of the ball is n

ioda

Answer:

13.5

Explanation:

Mass: 5kg

Initial Velocity: -15

Final Velocity: 12

Force: 10

We can use the equation: Vf = Vi + at

We need to find acceleration, and we can use the equation, F=ma,

We have mass and the force so it would look like this, 10=5a, and 5 times 2 would equal 10, so acceleration would be 2.

Now we have all the variables to find time.

Back to Vf = Vi + at, plug the numbers in, 12 = -15 + 2(t)

Plugging them in into desmos gives 13.5 for time.

4 0

2 years ago

A rock is thrown with a force of 500 N and an acceleration is 75 m/s^2. What is its mass?

artcher [175]

Answer:

We conclude that the mass of a rock with a force of 500 N and an acceleration of 75 m/s² is 6.7 kg.

Hence, option D is correct.

Explanation:

Given

Force F = 500 N

Acceleration a = 75 m/s²

To determine

Mass m = ?

Important Tip:

The mass of a rock can be found using the formula F = ma

Using the formula

$F = ma$

where

F is the force (N)

m is the mass (kg)

a is the acceleration (m/s²)

now substituting F = 500, and a = 75 m/s² in the formula

$F = ma$

$500 = m(75)$

switch sides

$m\left(75\right)=500$

Divide both sides by 75

$\frac{m\cdot \:75}{75}=\frac{500}{75}$

simplify

$m=\frac{20}{3}$

$m=6.7$ kg

Therefore, we conclude that the mass of a rock with a force of 500 N and an acceleration of 75 m/s² is 6.7 kg.

Hence, option D is correct.

7 0

3 years ago

A 0.80 kg object tied to the end of a 2.0 m string swings as a pendulum. At the lowest point of its swing, the object has a kine

devlian [24]

Answer:

3.32 m/s

Explanation:

From the law of conservation of energy, the sum of mechanical and kinetic energy should be equal to the 10 J given. Potential energy is given by mgh where m is mass, g is acceleration due to gravity and h is the height. For this case, $h= l(1-cos\theta)$ and l is string length, given as 2 m, \theta is given as 50 degrees. Kinetic energy is given by $0.5mv^{2}$ and it is this velocity that is unknown.

$10J=0.5\times 0.8kg\times v^{2}+ 0.8kg\times 9.81\times 2m(1-cos 50^{\circ})\\v\approx 3.32 m/s$

6 0

3 years ago

Please help don't for get to show work

emmasim [6.3K]

-- Bob covered a distance of (32m + 45m) = 77 meters.

-- His displacement is the straight-line distance and direction
from his starting point to his ending point.

The straight-line distance is

D = √(32² + 45²)
D = √(1,024 + 2,025)
D = √3,049 = 55.22 meters

The direction is the angle whose tangent is (32/45) south of east.

tan⁻¹(32/45) = tan⁻¹(0.7111...) = 35.42° south of east.

3 0

2 years ago