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Elanso [62]
3 years ago
5

Put the phase of mitosis or mitosis in order from first to last

Physics
2 answers:
vladimir1956 [14]3 years ago
7 0
The phases of mitosis in order from first to last are: Interphase, prophase, metaphase, anaphase, and telophase & cytokinesis.
Blizzard [7]3 years ago
4 0
Interphase, Prophase, Metaphase, Anaphase, Telophase, Cytokinesis
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Can someone please solve this
Zina [86]

Answer:

The gravity is pulling the diver downwards but the rotation of the body means gravity cant pull him down as quickly

Explanation:

8 0
3 years ago
A 65 Kg roller-blade is accelerating at 5 m/s/s across the side walk. What force would be necessary for this acceleration to occ
Neporo4naja [7]
Newton's second law states that the force applied to an object is equal to the product between the mass m of the object and its acceleration a:
F=ma
Using m=65 kg and a=5 m/s^2, we can find the value of the force applied to the roller-blade to obtain this acceleration:
F=(65 kg)(5 m/s^2)=325 N
3 0
3 years ago
According to the big-bang theory how the universe might end?
Troyanec [42]

Answer:

<em>If the Universe holds enough matter, including dark matter, the combined gravitational attraction of everything will gradually halt this expansion and precipitate the ultimate collapse. Over time, galaxies, then individual stars, will smash into each other more frequently, killing off any life on nearby planets.</em>

3 0
3 years ago
the pull of gravity on mars is 3.7m/s^2. if a astronaut on mars lifts a 10 kg rock 1 m off the ground, just to see whats under i
Elanso [62]
Gravitational potential energy can be calculated using the formula:

PE_{grav} =mgh

Where:
PEgrav = Gravitational potential energy
m= mass
g = acceleration due to gravity
h = height

On Earth acceleration due to gravity is a constant 9.8 but since the scenario is on Mars, the pull of gravity is different. In this case, it is 3.7, so we will use that for g.

So put in what you know and solve for what you don't know. 
m = 10kg
g = 3.7m/s^2
h = 1m

So we put that in and solve it. 
PE_{grav} =mgh
PE_{grav} =(10kg)(3.7m/s^{2})(1m)
PE_{grav} =37J


7 0
4 years ago
Identify forces between two objects which are inversely proportional to the square of the distance between them. i. nuclear forc
nikdorinn [45]
The force between two celestial bodies is a Newtonian gravitational force. 
It is also called Newton's law of universal gravitation. We can write it down mathematically in the following way:
F=G \frac{ m_{1} m_{2} }{ r^{2}}
We can see from this formula that gravitational force is <span>inversely proportional to the square of the distance between bodies.
The electrostatic force between two charges is Coulombs force. We can write it down like this: 
</span>F= k_{e} \frac{ q_{1} q_{2} }{ r^{2}}
This force is also inversely proportional to the square of the distance between interacting particles.
The nuclear force is a little bit more complicated. It can be expressed using the so-called Yukawa potential, which has the following form:
V_{y} =- g^{2} \frac{ e^{-ur} }{r}
This interaction does not follow the inverse-square law.
The final answer should be 8.
3 0
3 years ago
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