3 years ago

Put the phase of mitosis or mitosis in order from first to last

2 answers:

vladimir1956 [14]3 years ago

7 0

The phases of mitosis in order from first to last are: Interphase, prophase, metaphase, anaphase, and telophase & cytokinesis.

Blizzard [7]3 years ago

4 0

Interphase, Prophase, Metaphase, Anaphase, Telophase, Cytokinesis

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During baseball practice, a batter hits a high flyball, and then runs in a straight line and catches it. which has the greater a

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They have the same velocity because their displacements (shortest line from point A to point B, which is a straight line) are the same and they meet at the same time.

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3 years ago

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A soccer player kicks a ball horizontally at 28 m/s from a bridge and hits the ground after 1.5 s. What is the range of the ball

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Answer:

Explanation:

range of ball = u×t

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2 years ago

Consider two air-filled parallel-plate capacitors with circular plates. Capacitor 1 has a distance between plates d and plate ra

sergey [27]

Answer:

1/8 x C

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The capacitance of parallel plate capacitor

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C = ε₀ A /d

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radius = R/2

Area = A / 4

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4 0

3 years ago

Which of the following does not affect electrical resistance?

Gnesinka [82]

I think it's A) colour

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3 years ago

A spring of negligible mass stretches 3.00 cm from its relaxed length when a force of 7.50 N is applied. A 0.500-kg particle res

garri49 [273]

Answer:

ω = 22.36 Hz

f = 3.56 Hz

T = 0.28 s.

Explanation:

a) The angular frequency (ω), can be calculated using the following equation:

$\omega = \sqrt{\frac{k}{m}} = \sqrt{\frac{F}{x*m}}$

Where:

k: is the spring constant = F/x

m: is the mass of the particle = 0.500 kg

F: is the force applied = 7.50 N

x: is the displacement = 3.00 cm = 0.03 m

$\omega = \sqrt{\frac{7.50 N}{0.03 m*0.500 kg}} = 22.36 s^{-1} = 22.36 Hz$

Therefore, the angular frequency of the motion is 22.36 Hz.

b) To find the frequency (f) we can use the next equation:

$f = \frac{\omega}{2 \pi} = \frac{22.36 Hz}{2 \pi} = 3.56 Hz$

Hence, the frequency of the motion is 3.56 Hz.

c) The period (T) is equal to:

$T = \frac{1}{f} = \frac{1}{3.56 Hz} = 0.28 s$

Therefore, the period of the motion is 0.28 s.

I hope it helps you!

4 0

4 years ago