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Zarrin [17]
3 years ago
7

I don't understand how to do this problem.​

Mathematics
2 answers:
Alinara [238K]3 years ago
4 0

Answer:

2/3 * 6a+ 2/3 +9 = 21.6

a = 3.9

Step-by-step explanation:

2/3 ( 6a+9) = 21.6

Distribute

2/3 * 6a+ 2/3 +9 = 21.6

4a + 6 = 21.6

Subtract 6 from each side

4a = 15.6

Divide each side by 4

4a/4 = 15.6/4

a =3.9

andriy [413]3 years ago
3 0

Answer:

First blank: 6a

Second blank: 2/3

Third blank: 21.6

Fourth blank: 3.9

Step-by-step explanation:

Basically, all you need to do is distribute the 2/3 to the stuff inside the parentheses. That means in the first blank, write 6a inside since you're multiplying 2/3 and 6a, and then in the second blank you write 2/3 since you're multiplying 2/3 and 9 together.

2/3*6a+2/3*9 = 21.6 is what you should have.

Now, just solve for a.

4a+6 = 21.6

4a=15.6

a=3.9

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Wittaler [7]
Hello!

2(x + 9) = 4(x + 7) + 2

Distribute the 2

2x + 18 = 4(x + 7) + 2

Distribute the 4

2x + 18 = 4x + 28 + 2

Combine like terms

2x + 18 = 4x + 30

Subtract 18 from both sides

2x = 4x + 12

Subtract 4x from both sides

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Divide both sides by -2

x = -6

Where she did something different than me is her mistake

Hope this helps!
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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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3 years ago
Ship A and Ship B are 120 km apart when they pick up a distress call from another boat. Ship B estimates that they are 70 km awa
oksian1 [2.3K]

Answer:

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Step-by-step explanation:

a=120  km

b=70  km

β=28 degrees ( ∘)

 

b^2=(a^2)+(c^2)−2ac*cosβ  

70^2 =(120^2 )+(c^2)−2⋅ 120⋅ c⋅ cos(28∘ )  

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note p, q, and r are replacement variables in the Pythagorean theorem since a, b, and c are already in use

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D=(q^2 ) −4pr=(211.907^2 )−4⋅1⋅9500=6904.75561996  

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c_{1,2}  =   (−q±  \sqrt{D}   )/2p=(211.91±\sqrt{6904.76})/2

​c_{1,2}  =105.95371114±41.5474295834  

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c_{1}=147.501140726  

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5 0
3 years ago
15 counters in the whole set. How many are there in 2/3 of the set?
muminat
Look at this video: https://www.khanacademy.org/math/cc-fifth-grade-math/cc-5th-fractions-topic/cc-5th-multiplying-fraction-whole-number-product



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