Answer:
Step 3.
Operation error, where the sign on the number changes from -ve to +ve where shifted to the left side of the equation.
Step-by-step explanation:
Given that 2(10 - 13x) + 9x = -34x + 60
<u>Step 1. Distribute</u>
20-26x+9x=-34x+60
<u>Step 2: Combine like Terms</u>
20-17x=-34x+60 -------------------------(-26x+9x = -17x)
<u>Step 3: subtraction property of equality</u>
-17x+34x=60-20--------------------- (60-20 =40)
-17x+34x=40
<u>Step 4 :Addition property of Equality</u>
-17x+34x=40-------------------(-17x+34x =17x)
17x=40
<u>Step 5: Division property of Equality</u>
17x=40
17x/17 = 40/17
x=40/17
Answer
x=40/17
<u>Errors</u>
In step 3
-17x+34x = 17 x and not 51x
In step 5
-51x=40
x=-40/51 (not the other way round, -51/40) however correct operation is supposed to be;
17x=40, hence x =40/17
The answer to the problem that you need help with is -34
There seems to be one character missing. But I gather that <em>f(x)</em> needs to satisfy
•
divides 
•
divides 
I'll also assume <em>f(x)</em> is monic, meaning the coefficient of the leading term is 1, or

Since
divides
, and

where
is degree-2, and we can write it as

Now, we have

so if
divides
, then
is degree-2, so
is degree-4, and we can write

where
is degree-1.
Expanding the left side gives

and dividing by
leaves no remainder. If we actually compute the quotient, we wind up with

If the remainder is supposed to be zero, then

Adding these equations together and grouping terms, we get

Then
, and you can solve for <em>a</em> and <em>b</em> by substituting this into any of the three equations above. For instance,

So, we end up with

Answer:
<em>She needs to add no fertilizer, option A)</em>
Step-by-step explanation:
<u>Equation of a Line:</u>
According to the conditions of the question, being x the ounces of fertilizer Olivia adds to the soil, and y the number of blooms each rose bush has, the relation between them is

It's bee required to compute the value of x such that the roses have 4 blooms, thus

Solving for x


This means she needs to add no fertilizer, option A)