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3 years ago

Help again please and can someone provide a step by step explaintion on how to solve it

Mathematics

1 answer:

pashok25 [27]3 years ago

6 0

I think it’s c bc it’s descending meaning it’s a negative but I might be wrong bc I haven’t practice this in a while

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rodikova [14]

Answer:

Step 3.

Operation error, where the sign on the number changes from -ve to +ve where shifted to the left side of the equation.

Step-by-step explanation:

Given that 2(10 - 13x) + 9x = -34x + 60

Step 1. Distribute

20-26x+9x=-34x+60

Step 2: Combine like Terms

20-17x=-34x+60 -------------------------(-26x+9x = -17x)

Step 3: subtraction property of equality

-17x+34x=60-20--------------------- (60-20 =40)

-17x+34x=40

Step 4 :Addition property of Equality

-17x+34x=40-------------------(-17x+34x =17x)

17x=40

Step 5: Division property of Equality

17x=40

17x/17 = 40/17

x=40/17

Answer

x=40/17

Errors

In step 3

-17x+34x = 17 x and not 51x

In step 5

-51x=40

x=-40/51 (not the other way round, -51/40) however correct operation is supposed to be;

17x=40, hence x =40/17

4 0

3 years ago

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What is the solution of -3x squared minus 2x minus 28 equals zero

Kamila [148]

The answer to the problem that you need help with is -34

6 0

3 years ago

53. Which of the following diagrams show a pair of corresponding angles?

sashaice [31]

Answer:

Diagram A is correct one

3 0

3 years ago

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Find a polynomial $f(x)$ of degree $5$ such that both of these properties hold: $\bullet$ $f(x)$ is divisible by $x^3$. $\bullet

frosja888 [35]

There seems to be one character missing. But I gather that f(x) needs to satisfy

• $x^3$ divides $f(x)$

• $(x-1)^3$ divides $f(x)^2$

I'll also assume f(x) is monic, meaning the coefficient of the leading term is 1, or

$f(x) = x^5 + \cdots$

Since $x^3$ divides $f(x)$ , and

$f(x) = x^3 p(x)$

where $p(x)$ is degree-2, and we can write it as

$f(x)=x^3 (x^2+ax+b)$

Now, we have

$f(x)^2 = \left(x^3p(x)\right)^2 = x^6 p(x)^2$

so if $(x - 1)^3$ divides $f(x)^2$ , then $p(x)$ is degree-2, so $p(x)^2$ is degree-4, and we can write

$p(x)^2 = (x-1)^3 q(x)$

where $q(x)$ is degree-1.

Expanding the left side gives

$p(x)^2 = x^4 + 2ax^3 + (a^2+2b)x^2 + 2abx + b^2$

and dividing by $(x-1)^3$ leaves no remainder. If we actually compute the quotient, we wind up with

$\dfrac{p(x)^2}{(x-1)^3} = \underbrace{x + 2a + 3}_{q(x)} + \dfrac{(a^2+6a+2b+6)x^2 + (2ab-6a-8)x +2a+b^2+3}{(x-1)^3}$

If the remainder is supposed to be zero, then

$\begin{cases}a^2+6a+2b+6 = 0 \\ 2ab-6a-8 = 0 \\ 2a+b^2+3 = 0\end{cases}$

Adding these equations together and grouping terms, we get

$(a^2+2ab+b^2) + (2a+2b) + (6-8+3) = 0 \\\\ (a+b)^2 + 2(a+b) + 1 = 0 \\\\ (a+b+1)^2 = 0 \implies a+b = -1$

Then $b=-1-a$ , and you can solve for a and b by substituting this into any of the three equations above. For instance,

$2a+(-1-a)^2 + 3 = 0 \\\\ a^2 + 4a + 4 = 0 \\\\ (a+2)^2 = 0 \implies a=-2 \implies b=1$

So, we end up with

$p(x) = x^2 - 2x + 1 \\\\ \implies f(x) = x^3 (x^2 - 2x + 1) = \boxed{x^5-2x^4+x^3}$

6 0

3 years ago

Olivia is growing roses and keeps track of how much fertilizer (in ounces) she adds to the soil and how many blooms each rose bu

dusya [7]

Answer:

She needs to add no fertilizer, option A)

Step-by-step explanation:

Equation of a Line:

According to the conditions of the question, being x the ounces of fertilizer Olivia adds to the soil, and y the number of blooms each rose bush has, the relation between them is

$y = 1.345x + 4$

It's bee required to compute the value of x such that the roses have 4 blooms, thus

$1.345x + 4=4$

Solving for x

$1.345x=4-4=0$

$x=0$

This means she needs to add no fertilizer, option A)

8 0

4 years ago

Read 2 more answers