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3 years ago

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Since opening night, attendance at play A has increased steadily, while attendance at play B first rose and then fell. Equations

modeling the daily attendance y at each play are shown below, Where x is the number of days since opening night. On what day(s) was the attendance the same at both plays? What was the attendance? Play A: y=15x+76 play B: y=-x^2+36x-4

2 answers:

lbvjy [14]3 years ago

8 0

Answer:

(5,151) and (16,316) are days with equal attendance for both plays.

Step-by-step explanation:

brainly.com/question/8102047

quester [9]3 years ago

5 0

The correct answer is 5,101

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What is 5/11 minus negative 4/11

MA_775_DIABLO [31]

<u><em>Answer: 1/11 and 0.09=0.10</em></u>

Step-by-step explanation:

subtract by the numbers. subtract it's to take away one number from to another from the difference between the numbers.

5-4/11

5-4=1

=1/11

You can also round up to the nearest hundredths is 0.10.

Hope this helps!

Thanks!

Have a great day!

5 0

3 years ago

Read 2 more answers

Does anyone know the answer to this scale and unit conversion GED math problem? Thank you very much!

aliya0001 [1]

Answer:

Flour $5\dfrac{1}{2}\ c$

Sugar $2\dfrac{2}{3}\ c$

Butter $1\dfrac{1}{2}\ c$

Eggs $2$

Baking powder $7\ t$

Vanilla extract $3\ t$

Step-by-step explanation:

There will be 16 people at the party. Each person will eat 3 cookies, so all people will eat $16\cdot 3=48$ cookies.

Given cookie recipe makes 24 cookies, so to make 48 cookies you need

$48:24=2$ portions.

Thus,

1 portion 2 portions

Flour $2 \dfrac{3}{4}\ c$ $2\dfrac{3}{4}\cdot 2=2\cdot 2+\dfrac{3}{4}\cdot 2=4+\dfrac{3}{2}=4+1 \dfrac{1}{2}=5\dfrac{1}{2}\ c$

Sugar $1\dfrac{1}{3}\ c$ $1\dfrac{1}{3}\cdot 2=1\cdot 2+\dfrac{1}{3}\cdot 2=2+\dfrac{2}{3}=2\dfrac{2}{3}\ c$

Butter $\dfrac{3}{4}\ c$ $\dfrac{3}{4}\cdot 2=\dfrac{3}{2}=1\dfrac{1}{2}\ c$

Eggs $1$ $1\cdot 2=2$

Powder $3\dfrac{1}{2}\ t$ $3\dfrac{1}{2}\cdot 2=3\cdot 2+\dfrac{1}{2}\cdot 2=6+1=7\ t$

Vanilla $1\dfrac{1}{2}\ t$ $1\dfrac{1}{2}\cdot 2=1\cdot 2+\dfrac{1}{2}\cdot 2=2+1=3\ t$

8 0

3 years ago

X²+Y²=250 and XY=117<br> What are the values of X and Y?

yan [13]

Answer:

<h3> x = -9, y = -13 </h3><h3> or x = 13, y = 9</h3><h3> or x = -13, y = -9</h3><h3> or x = 9, y = 13</h3>

Step-by-step explanation:

$x^2+y^2=250\\\\x^2-2xy+y^2+2xy=250\\\\(x-y)^2=250-2xy\\\\(x-y)^2=250-2\cdot117\\\\ (x-y)^2=16\\\\x-y=4\qquad\qquad\vee\qquad \qquad x-y=-4\\\\x=4+y \qquad\qquad \vee\qquad\qquad x=-4+y\\\\(y+4)y=117\qquad\vee\qquad\quad (y-4)y=117\\\\y^2+4y-117=0\qquad\vee\qquad y^2-4y-117=0\\\\y=\dfrac{-4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\qquad\vee\qquad y=\dfrac{4\pm\sqrt{4^2-4(-117)}}{2\cdot1}\\\\y=\dfrac{-4\pm\sqrt{16+468}}{2}\qquad\ \ \vee\qquad y=\dfrac{4\pm\sqrt{16+468}}{2}$

$y_1=\dfrac{-4-22}{2}\ ,\quad y_2=\dfrac{-4+22}{2}\ ,\quad y_3=\dfrac{4-22}{2}\ ,\quad y_4=\dfrac{4+22}{2}\\\\y_1=-13\ ,\qquad y_2=9\ ,\qquad\quad\qquad\ y_3=-9\ ,\qquad y_4=13\\\\x_{1,2}=4+y_{1,2}\qquad\qquad\qquad\qquad\qquad x_{3,4}=-4+y_{3,4}\\\\x_1=-9\ ,\qquad x_2=13\ ,\qquad\quad\qquad x_3=-13\ ,\qquad x_4=9$

6 0

3 years ago

If y is proportional to x and y = -15 when x = -20, what is the value of x when y = 12?

Alex

When y=-15, x=-20. So subtract x from y, you will get that y= 0 and x=-5. Add 12 to both and you have your answer, x=7 and y=12

7 0

3 years ago

I dont know how you’d work this out, someone please help!<br><br> Thanks

Alinara [238K]

Answer:

see photo attached for analysis

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2 years ago