The two planes are flying in opposite directions.One plane travels at 560miles per hour and the other travels at a speed of 500 miles per hour. As time proceeds, they would travel further from each other and that can be described by the equation that follows:
560(t)+500(t) =2000, since we are given a 2000 distance limit. Then we are to find the time when they are at this distance. Solve for t, which is equal to 0.53 hours or 32 minutes.
-7 × -3 = 21
(Negative × Negative = Positive)
21 × 4 = 84
Answer = 84
Hope this helped☺☺
$28 because Minimum is the least or smallest amount REMEMBER THIS
Answer:
650 miles
Step-by-step explanation:
Plan A 49+.12m where m is the miles
Plan B = 36+.14m
We want where they cost the same, so set them equal
49+.12m = 36+.14m
Subtract .12m from each side
49+.12m-.12m = 36+.14m-.12m
49 = 36+.02m
Subtract 36 from each side
49 - 36 = 36-36+.02m
13 = .02m
Divide each side by .02
13/.02 = .02m/.02
650 = m
Answer:
(6,8)
Step-by-step explanation:
You can just substitute the options into the inequalities
e.g. For option 1, you can put x=6, and you will find the RHS is smaller than LHS in both inequalities.
