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weeeeeb [17]
3 years ago
9

Please Help Help Help

Mathematics
1 answer:
Blababa [14]3 years ago
5 0

EDCB is a rectangle, so:

ED = BC = 12

DC = EB = 29

We know that,

= AB = AE + EB

= 34 = AE + 29

= 34 - 29 = AE

= 5 = AE

Now, in triangle EAD, by pythagonas theoram:

= H² = P² + B²

= H² = 5² + 12²

= H² = 25 + 144

= H = √169

= H = 13

So, AD = 13 cm

_________________

Simpooooool

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Find the distance, c, between (–3, 4) and (2, –3) on the coordinate plane. Round to the nearest tenth if necessary.
andriy [413]

Using the distance formula, the distance between (-3, 4) and (2, -3) is: 8.6 units.

<h3>What is the distance formula?</h3>

Distance formula for calculating the distance between two points on a coordinate plane is given as: d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}.

Let,

(-3, 4) = (x1, y1)

(2, -3) = (x2, y2)

Plug in the values

c = \sqrt{(2 - (-3))^2 + (-3 - 4)^2} \\\\c = \sqrt{74} \\\\

c = 8.6 units.

Therefore, using the distance formula, the distance between (-3, 4) and (2, -3) is: 8.6 units.

Learn more about distance formula on:

brainly.com/question/661229

5 0
2 years ago
Which expression is equivalent to (4^−3)^−6?<br><br>1. 4^-18<br>2. 4^18<br>3. 4^-9<br>4. 4^3
malfutka [58]

Answer:

4^18

Step-by-step explanation:

4^18 = 2^36

(4^−3)^−6? = 2^36

Please visit: https://youtu.be/_0Ft9HdNg5c

Thanks.

8 0
3 years ago
6(u+3) Use the distributive property to remove the parentheses 6(u+3
Vlad [161]

Answer:

6u+18

Step-by-step explanation:

6*u=6u and 6*3=18

8 0
2 years ago
Explain WHAT WOULD HAPPEN TO motion IF friction DID NDT EXIST.
MA_775_DIABLO [31]

Answer:

If friction did not exist, it would be hard for us to slow down in running, or putting breaks on a car, and more!

If friction did not exist, your car will slide down the road even if you try your best to put the brakes on a car. Friction is a very important force to slow down things that are moving very fast

Step-by-step explanation:

Hoped this helped.

GeniusUser

5 0
2 years ago
What is the answer to the question
S_A_V [24]

The equation of the parallel line is y = –2x – 11.

Solution:

Given equation of the line is y = –2x – 5.

Slope of this line is (m_1) = –2

To write the equation parallel to this line and passes through (–4, –3).

<em>If two lines are parallel, then they have the same slope.</em>

\Rightarrow m_1=m_2

\Rightarrow m_2 =-2

<u>Point-slope formula:</u>

y-y_1=m(x-x_1)

Substitute the given values in the formula, we get

y-(-3)=-2(x-(-4))

y+3=-2(x+4)

y+3=-2x-8

Subtract 3 from both sides of the equation.

y+3-3=-2x-8-3

y=-2x-11

Hence the equation of the parallel line is y = –2x – 11.

5 0
3 years ago
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