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inn [45]
3 years ago
11

Which of the following sets of ordered pairs represents a function?

Mathematics
2 answers:
Artemon [7]3 years ago
8 0

Answer:

B

{(8,-9), (-8,-5), (8-7), (-8,-6)}

Step-by-step explanation:

A function can have two X values but not two Y values

Lubov Fominskaja [6]3 years ago
4 0

Answer:

<h2>D.</h2><h2>{(-9,8), (-5,-8), (-7,8), (-6,-8)}</h2>

Step-by-step explanation:

A function is defined as the relation between two sets with an specific characteristic:

  • If each x-value has only one y-value assigned, then the expression it's a function.
  • If each x-value has more than one y-value image, then the expression it's not a function, it's just a relation.

So, in this problem, we have to look for this characteristic. Option A has two points with the same x-value and different y-value assigned, so it's not a function. Option B has two y-values assigned for x=8, so it's not a function either. Option C is not a function because x=13 has to different images y=-3 and y=0.

At last, option D represent a function, because each x-value has only one image: {(-9,8), (-5,-8), (-7,8), (-6,-8)}

It's important to notice that, one y-value can have different x-values assigned, that's a function, but it cannot happen in the opposite way, one x-value with more than one y-value assigned.

Therefore, the right answer is D.

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Answer:

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v + 6 = 92

v + 6 = 92

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(5 points) An urn contains two blue balls denoted by B1 and B2, and three white balls denoted by W1, W2 and W3. One ball is draw
never [62]

Answer:

The probability of the event that first ball that is drawn is blue  is \frac 25.

Step-by-step explanation:

Probability:

If S is is an sample space in which all outcomes are equally likely and E is an event in S, then the probability of E,denoted P(E) is

P(E)=\frac{\textrm{The number of outcomes E}}{\textrm{The total number outcomes of S}}

Given that,

An urn contains two balls B₁ and  B₂ which are blue in color and W₁,W₂ and W₃ which are white in color.

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=5²

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B₁B₁ , B₁B₂ , B₁W₁ , B₁W₂ , B₁W₃ , B₂B₁ , B₂B₂ ,  B₂W₁ , B₂W₂ , B₂W₃

The number of event that the first ball that is drawn is blue is

=10.

The probability of the event that first ball that is drawn is blue  is

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y-3=-12(x-5)

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