Question

The projectile motion of an object can be modeled using h(t) = gt2 + v0t + h0, where g is the acceleration due to

Answer 1

The answer is C!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

Answer:

option C

Step-by-step explanation:

The projectile motion of an object can be modeled using h(t) = gt2 + v0t + h0, where g is the acceleration due to gravity. The acceleration due to gravity is –9.8 m/s2

An object is launched at an initial velocity of 20 meters per second and an initial height of 60 meters.

g= -9.8, v0 = 20  and h0 = 60

So the equation becomes

$h(t)= -9.8t^2 +20t +60$

When the object hit the ground the height =0 so we replace h(t)=0

Apply quadratic formula

$t= \frac{-b+-\sqrt{b^2-4ac}}{2a}$

a= -9.8 , b=20  and c= 60

$t= \frac{-20+-\sqrt{(20)^2-4(-9.8)(60)}}{2(-9.8)}$