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Lostsunrise [7]
2 years ago
12

Solve the inequality. 4a < 52

Mathematics
1 answer:
jeka57 [31]2 years ago
7 0

4a<52

All you have to do is divide 4 from a and 52.

4a<52

/4   /4

a<13

a<208 √

a<56 √

a<48 √

a<13 X

So the odd one out is a<13

---

hope it helps

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To determine which of the rectangles has a different area, the areas of the four rectangles must be calculated. The rectangle with a different area is rectangle b

The dimension of the 4 rectangles are:

a. length: 4x and width: 4

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d. length: 16x and width: 1

The area of a rectangle is:

Area = Length \times Width

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Area = 16x

<u>Rectangle (b)</u>

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Area = 11x

<u>Rectangle (c)</u>

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Rectangles (a), (c) and (d) have the same area (i.e. 16x) while rectangle (b) has 11x as its area.

Hence, the rectangle with a different area is rectangle (b).

Read more about areas of rectangles at:

brainly.com/question/14383947

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