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3 years ago

Solve the inequality. 4a < 52

Mathematics

1 answer:

jeka57 [31]3 years ago

7 0

4a<52

All you have to do is divide 4 from a and 52.

4a<52

/4 /4

a<13

a<208 √

a<56 √

a<48 √

a<13 X

So the odd one out is a<13

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hope it helps

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It takes Chris 6.5 hours to drive 455 miles. If he travels at the same rate, how long will it take him to drive 2100 miles?

mart [117]

First let’s divided 455 by 6.5 to figure out how far he travels in 1 hour which is equal to 70, now let’s do 2100 divided by 70, it will take 30 hours for him to drive 2100 miles.

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3 years ago

Find the perimeter and area of the rectangle.<br> 6.9 in<br> 2.4 in

saveliy_v [14]

Answer:The perimeter = 18.6 , The area= 16.56

Step-by-step explanation: The perimeter is all sides added together and there are four sides and two sides are even , so there are two ways to find it. {1} 6.9x2=13.8 , 2.4x2=4.8; 13.8+4.8=18.6…{2} 6.9+6.9+2.4+2.4=18.6.

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3 years ago

E(-2,-1) and F(-2,-5) what is the distance in each pair of points

Alik [6]

Answer:

6 units

Step-by-step explanation:

E(-2 , -1) = (x1 , y1)

F(-2 , -5) = (x2 , y2)

distance = $\sqrt{(x2 - x1)^2 + (y2 - y1)^2}$

= $\sqrt{(-2 - (-2))^2 + (-5 - (-1))^2}$

= $\sqrt{(-2 + 2)^2 + (-5 + 1)^2$

= $\sqrt{0^2 + 6^2}$

= $\sqrt{36}$

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3 years ago

The surface distance between 2 points on the surface of a cube is the length of the shortest path on the surface of the cube tha

VLD [36.1K]

Answer:

9.66cm

Step-by-step explanation:

Given a cube, the Surface Distance between two points is defined as the length of the shortest path on the surface of the cube that joins the 2 points.

For a cube of length 4cm, we are to determine the surface distance between the lower left vertex on its front face and the upper right vertex on its back face.

In the produced diagram,

The front face is denoted by the square ABCD
The back face is denoted by square EFGH.
The distance we are to determine is |AX|.

The shortest distance between A and C is the diagonal that joins point A to point C.

Using Pythagoras theorem,

$|AC|=\sqrt{|AB|^2+|BC|^2} \\=\sqrt{4^2+4^2}\\=\sqrt{32} \\|AC|=4\sqrt{2} cm$

Therefore, the shortest distance between A and point X

=|AC|+|CX|

$=4\sqrt{2} +4\\=9.66cm$

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4 years ago

When a certain tree was first planted, it was 4 feet tall, and the height of the tree increased by a constant amount each year f

SCORPION-xisa [38]

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4 years ago