If 1 inch = 65 meters then 5 inches = 325 meters
Answer:
Step-by-step explanation:
an=a1+d(n-1)
an=-2n-1
next term a5=-11
hope helps
(w,k)
that is amount of women and children lefton original side
ok, first realize you must get children across first because who will row the boat back
first trip: 10min, 2 children across, (3,1)
2nd trip: 20min, 1 kid cross back (3,2)
3rd trip: 30min, 2 kids cross (3,0)
4th trip: 40 min, 1 kid cross baack (3,1)
5th trip: 50 min, 1 woman cross (2,1)
6th trip: 60 min, 1 kid cross back (2,2)
7th trip: 70 min, 1 woman cross (1,2)
8th trip: 80 min, 1 kid cross back (1,1)
9th trip: 90 min, 1 woman cross (0,1)
10th trip: 100min, 1 kid cross back (0,2)
11th trip: 110 min, 2 kids cross back (0,0)
min time is 110 mins or 1hr 50min
Answer:
(a) 0.007238 or 07238%
(b) 0.003468 or 0.3468%
Step-by-step explanation:
(a) Since all it takes is one defective rivet for a seam to be reworked. The probability of a defective rivet 'p' for 16% of seams needing reworking is:
![1-(1-p)^{24} = 0.16\\1-p = \sqrt[24]{0.84}\\p=0.007238](https://tex.z-dn.net/?f=1-%281-p%29%5E%7B24%7D%20%3D%200.16%5C%5C1-p%20%3D%20%5Csqrt%5B24%5D%7B0.84%7D%5C%5Cp%3D0.007238)
The probability that a rivet is defective 0.007238 or 0.7238%.
(b) To ensure that only 8% of seams need reworking, the probability 'p' must be:
![1-(1-p)^{24} = 0.08\\1-p = \sqrt[24]{0.92}\\p=0.003468](https://tex.z-dn.net/?f=1-%281-p%29%5E%7B24%7D%20%3D%200.08%5C%5C1-p%20%3D%20%5Csqrt%5B24%5D%7B0.92%7D%5C%5Cp%3D0.003468)
In order to ensure that only 8% of all seams need reworking, the probability of a defective rivet should be 0.003468 or 0.3468%.
Answer:
wheres the table above
Step-by-step explanation: