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DedPeter [7]
2 years ago
12

I’LL GIVE YOU BRILLIANCE (it’s question 15)

Mathematics
1 answer:
Ket [755]2 years ago
3 0

Answer:

one 4 Two yes And 4

Step-by-step explanation:

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3 years ago
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HELP!!!! Graduation depends on you guys today
Nonamiya [84]
There are the combinations that result in a total less than 7 and at least one die showing a 3:

[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36

There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:

1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36

Therefore, the required probability is: 5/36
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3 years ago
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3 years ago
I need help with this problem Geometry
FromTheMoon [43]
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4 0
2 years ago
Josiah invests $360 into an account that accrues 3% interest annually. Assuming no deposits or withdrawals are made, which equat
vlabodo [156]

Answer:

y = 360(1.03)x

Step-by-step explanation:

F = P x (1 + i)^n

F is the future worth, P is the present worth, I will be the interest rate, and n is the number of years. F = ($360)(1.03)^x

The principal amount of the money = $360

Annual rate of interest = 3%

Thus, the amount after x years which is increased by 3%.

Since, this amount represented by y,

The required equation that represents the amount of money in Josiah’s  account, y, after x years is, = 360(1+\frac{3}{100} )^x\\ = 360(1+0.03 )^x\\ = 360(1.03 )^x

This amount represented by y,

Therefore, the required equation that represents the amount of money in Josiah’s account, y, after x years is,

y = 360(1.03 )^x

Hope this helps you!

Have a nice evening! ;)

5 0
3 years ago
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