Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
Jon will be able to run 2 trails because 1/6 time 2 equals 2/6 you can simplify it to 1/3 and 1/3 + 1/3= 2/3
Answer:
77
Step-by-step explanation:
that is the answer i got i did a quiz with the same question not too long and i got a 100 and i putt 77 aas my answer!!!!!!!!1
Answer:
Index of refraction of transparent is 1.48
Step-by-step explanation:
Snell's law states that;
n1(sinθ1) = n2(sinθ2)
Where;
n1 and n2 represent the indices of refraction for the two media, and θ1 and θ2 are the angles of incidence and refraction that the ray R makes with the normal.
In this question;
n1 = 1;
θ1 = 43.8°
θ2 = 19.3°
n2 is unknown.
Thus using Snell's law, we have;
1 x sin 43.8 = n2 x sin 19.3
n2 = (sin 43.8)/sin 19.3
n2 = 1.48
27.98ft
You can get this by using the tangent formula. The answer exactly expressed is 60tan25.
