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choli [55]
3 years ago
12

How to rewrite 11/12 in two different ways

Mathematics
2 answers:
Gennadij [26K]3 years ago
8 0

Step-by-step explanation:

As a decimal you divide 11 by 12 which is 0,916 (6 repeating)

now as a percent you multiply this decimal by 100 which is 91.6 (6 repeating)%

KatRina [158]3 years ago
3 0

Answer:

1) 33/36 = 11/12

2) 22/24 = 11/12

Step-by-step explanation:

Hope it helps you! Please give me Brainlest!

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Mr Kelly has a big pot of chili. He splits it into 9 bowls that each hold 1 1/8 cups. After filling those bowls, there is 1/2 cu
nirvana33 [79]
<h3>Answer:</h3>

10 5/8 cups

<h3>Explanation:</h3>

pot amount = 9 × (bowl amount) + (leftover amount)

... = 9 × (1 1/8) + 1/2

... = 9 × (1 + 1/8) + 4/8 . . . . . show 1 1/8 as a sum, rewrite 1/2 to 4/8

... = 9 + 9/8 + 4/8 . . . . . . . . eliminate parentheses using the distributive property

... = 9 + 13/8 . . . . . . . . . . . . add the fractions

... = 9 + 1 5/8 . . . . . . . . . . . convert from improper fraction to mixed number

... = 10 5/8 . . . . . cups . . . add the integer parts

7 0
3 years ago
wo balls are chosen randomly from an um containing 8 white, 4 black,and 2 orange balls. Suppose that we win $2 for each black ba
umka21 [38]

Answer:

The probability distribution is shown below.

Step-by-step explanation:

The urn consists of 8 white (<em>W</em>), 4 black (<em>B</em>) and 2 orange (<em>O</em>) balls.

The winning and losing criteria are:

  • Win $2 for each black ball selected.
  • Lose $1 for each white ball selected.

There are 8 + 4 + 2 = 14 balls in the urn.

The number of ways to select two balls is, {14\choose 2}=91 ways.

The distribution of amount won or lost is as follows:

Outcomes: WW  WO  WB  BB  BO  OO

X:                 -2      -1      1      4     2      0

Compute the probability of selecting 2 white balls as follows:

The number of ways to select 2 white balls is, {8\choose 2}=28 ways.

The probability of WW is,

P(WW)=\frac{n(WW)}{N}=\frac{28}{91}=0.3077

Compute the probability of selecting 1 white ball and 1 orange ball as follows:

The number of ways to select 1 white ball and 1 orange ball is, {8\choose 1}\times {2\choose 1}=16 ways.

The probability of WO is,

P(WO)=\frac{n(WO)}{N}=\frac{16}{91}=0.1758

Compute the probability of selecting 1 white ball and 1 black ball as follows:

The number of ways to select 1 white ball and 1 black ball is, {8\choose 1}\times {4\choose 1}=32 ways.

The probability of WB is,

P(WB)=\frac{n(WB)}{N}=\frac{32}{91}=0.3516

Compute the probability of selecting 2 black balls as follows:

The number of ways to select 2 black balls is, {4\choose 2}=6 ways.

The probability of BB is,

P(BB)=\frac{n(BB)}{N}=\frac{6}{91}=0.0659

Compute the probability of selecting 1 black ball and 1 orange ball as follows:

The number of ways to select 1 black ball and 1 orange ball is, {4\choose 1}\times {2\choose 1}=8 ways.

The probability of BO is,

P(BO)=\frac{n(BO)}{N}=\frac{8}{91}=0.0879

Compute the probability of selecting 2 orange balls as follows:

The number of ways to select 2 orange balls is, {2\choose 2}=1 ways.

The probability of OO is,

P(OO)=\frac{n(OO)}{N}=\frac{1}{91}=0.0110

The probability distribution of <em>X</em> is:

Outcomes:    WW     WO        WB         BB        BO         OO

X:                    -2          -1            1            4            2            0

P (X):           0.3077  0.1758  0.3516  0.0659  0.0879  0.0110

3 0
4 years ago
Use the product property for radicals to simplify the following radical expressions as much as possible. Square root of 54
Svetllana [295]

Answer:

3*sqrt(6)

Step-by-step explanation:

1. sqrt(54) = sqrt(3^2*6)

2. factor our 3^2

8 0
3 years ago
How to answer this question
12345 [234]
Flip the fraction to make the -3 exponet positive then it will be 9x^5/3x^3 which the answer would then be 3x^2
7 0
3 years ago
Read 2 more answers
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Vladimir79 [104]

Answer:14

Step-by-step explanation:

Well for the answer you just answer the opposite of the question

3 0
4 years ago
Read 2 more answers
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