Answer:
1. m = 45
2. x = -18
3. x = -13
4. x = 11
5. x = 19
6. v = 3
7. n = 208
8. b = -1
Step-by-step explanation:
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 152.5
For the alternative hypothesis,
µ ≠ 152.5
This is a two tailed test.
Since no population standard deviation is given, the distribution is a student's t.
Since n = 231
Degrees of freedom, df = n - 1 = 231 - 1 = 230
t = (x - µ)/(s/√n)
Where
x = sample mean = 148.9
µ = population mean = 152.5
s = samples standard deviation = 27.4
t = (148.9 - 152.5)/(27.4/√231) = - 2
We would determine the p value using the t test calculator. It becomes
p = 0.047
Since alpha, 0.05 > thanthere sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals the p value, 0.047, then we would reject the null hypothesis. Therefore, At a 5% level of significance, there is sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals
Answer:
66%
bcz out of 3 stuff in 100% is 66%
Answer is in the picture bellow
Step-by-step explanation:
|2x-3|=2x-1
need to consider two cases
(1) 2x-3<0 --> x<3/2
-(2x-3)=2x-1
x=1, and this is <3/2 so that's a valid solution
(2) 2x-3>=0 --> x>=3/2
2x-3=2x-1
-3 = -1 so there no solution for x>=3/2
The single solution is x=-1
