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3 years ago

Change the vertex form to standard quadratic form

Mathematics

1 answer:

Neko [114]3 years ago

5 0

Answer:

3x square-30x +29=0. i think thats the equatiom

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Given the binomials (x - 3), (x - 1), (x + 2), and (x + 3), which one is a factor of f(x) = 2x3 + 3x2 - 2x - 3?

spayn [35]

Answer:

(x-1) is factor of our function.

Step-by-step explanation:

We are given a function $f(x)=2x^{3} +3x^{2} -2x-3$ and we are asked to find the correct factor from the given options.

Let us factor out our polynomial.

$2x^{3} +3x^{2} -2x-3$

$x^{2} (2x+3)-1(2x+3)$

$(x^{2} -1)(2x+3)$

$(x+1)(x-1)(2x+3)$

Therefore, (x-1) is correct choice for factor of our polynomial.

3 0

3 years ago

Read 2 more answers

Carson took a total of 24 quizzes over the course of 4 weeks. How many weeks of school will Carson have to attend this quarter b

erastovalidia [21]

Answer:

9 weeks

Step-by-step explanation:

Assuming he takes equal number of quizzes weekly then having taken 24 quizzes within 4 weeks means for every week Carson took 24/4=6 quizzes per week.

With a target of 54 quizzes this quater and while maintaining 6 quizzes per week then Carson will take 54/6= 9 weeks to meet thw target.

Therefore, Carson needs 9 weeks this quater

7 0

4 years ago

PLEASE IS DUE IN A FEW MINUTES..

hjlf

Looks like you are screwed good luck:)

3 0

3 years ago

How do you get the answer to 1+1?

sveticcg [70]

Answer:

Step-by-step explanation:

If we take 1 and add another 1, you will get 2

5 0

3 years ago

Read 2 more answers

Help help help guys show you solution

Mars2501 [29]

Answer:

Step-by-step explanation:

1) y = 2x ----------(I)

x + y = 6 -----------(II)

Plug in y =2x in equation (II)

x + 2x = 6 {Add like terms}

3x = 6

x = 6/3

x = 2

Plugin x = 2 in (I)

y = 2*2

y = 4

Check:

LHS = x +y

= 2 + 4

= 6 = RHS

2)5x + 10y = 3 ------------(I)

x = (-1/2) y ------------(II)

Substitute x = (-1/2)y in (I)

$5*\frac{-1}{2}y + 10y = 3\\\\\frac{-5}{2}y+ \frac{10*2}{1*2}y = 3\\\\\frac{-5}{2}y+\frac{20}{2}y=3\\\\\frac{-5+20}{2}y = 3\\\\\frac{15}{2}y=3\\\\ y = 3*\frac{2}{15}\\\\ y = \frac{2}{5}$

Substitute y = (2/5) in equation (II)

$x = \frac{-1}{2}*\frac{2}{5}\\\\x = \frac{-1}{5}$

Check:

Substitute x and y value in equation (I)

$LHS = 5*\frac{-1}{5}+10*\frac{2}{5}\\\\ = -1 + 2*2\\\\ = -1 + 4\\ = 3 = RHS$

3) y - x = 3x + 2

y = 3x + 2 + x

y = 4x + 2 ---------------(I)

2x + 2y = 14 - y

2x + 2y +y = 14

2x + 3y = 14 ------------------(II)

Substitute y = 4x + 2 in equation (II)

2x + 3(4x +2) = 14

2x + 3*4x + 3*2 = 14

2x + 12x + 6 = 14

14x + 6 = 14

14x = 14 - 6

14x = 8

x = 8/14

x = 4/7

Substitute 'x' value in (I)

$y = 4*\frac{4}{7} +2\\\\y = \frac{16}{7}+2\\\\y= \frac{16}{7}+\frac{2*7}{1*7}\\\\y=\frac{16}{7}+\frac{14}{7}\\\\y=\frac{30}{7}$

Check:

 $LHS = 2x + 3y\\\\ = 2*\frac{4}{7}+3*\frac{30}{7}\\\\ = \frac{8}{7}+\frac{90}{7}\\\\=\frac{8+90}{7}\\\\=\frac{98}{7}\\\\=14 = RHS$ 

6 0

3 years ago