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Vlad1618 [11]
3 years ago
10

The tuition at a certain college was $29,793 last year and increased 5.3% from last year to the current year. How much is this y

ear's tuition?
Mathematics
2 answers:
jasenka [17]3 years ago
7 0
First convert 5.3% into a decimal 5.3% = .053
Then multiply by last years tuition 29,793 x .053 = 1,579.02 this is the amount that tuition is increased by. Now add this to last years tuition. 29793+ 1579.02 = 31,372.029
SCORPION-xisa [38]3 years ago
5 0

Answer:

the answer is 67

Step-by-step explanation:

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Ethan ill do 3 questions at a time :)
pashok25 [27]
1.) Number of Total Shirts = 220

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7 0
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Show Work Please Thank You
Misha Larkins [42]

Answer:

\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}

Step-by-step explanation:

We are given the trigonometric equation of:

\displaystyle{\sin 4x = \dfrac{\sqrt{3}}{2}}

Let u = 4x then:

\displaystyle{\sin u = \dfrac{\sqrt{3}}{2}}\\\\\displaystyle{\arcsin (\sin u) = \arcsin \left(\dfrac{\sqrt{3}}{2}\right)}\\\\\displaystyle{u= \arcsin \left(\dfrac{\sqrt{3}}{2}\right)}

Find a measurement that makes sin(u) = √3/2 true within [0, π) which are u = 60° (π/3) and u = 120° (2π/3).

\displaystyle{u = \dfrac{\pi}{3}, \dfrac{2\pi}{3}}

Convert u-term back to 4x:

\displaystyle{4x = \dfrac{\pi}{3}, \dfrac{2\pi}{3}}

Divide both sides by 4:

\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}

The interval is given to be 0 ≤ 4x < π therefore the new interval is 0 ≤ x < π/4 and these solutions are valid since they are still in the interval.

Therefore:

\displaystyle{x = \dfrac{\pi}{12}, \dfrac{\pi}{6}}

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