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ivann1987 [24]
4 years ago
15

Is -1/2n + 1 1/2n+3-n equivalent to 3? Explain plz

Mathematics
1 answer:
liraira [26]4 years ago
8 0
No, you can combine like terms like this (-1/2 + 11/2 -1)n +3 =3. Then you just simplify to see if the two sides of the equation match. You get 4n+3=3 which is not always true so the original equation is not true.

Feel free to ask any questions.

Don't forget to vote brainliest and follow me!!!
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The girls heights in inches are as follows:62,70,60,63,66,what is their average height?​
Gemiola [76]

Answer:

Average height = 64.2 inches

Step-by-step explanation:

Average = \frac{sum \ of \ the \ values }{number \ of\  value}

            =\frac{62 + 70 + 60 + 63 + 66}{5}\\\\=\frac{321}{5}\\\\=64.2 \ inches

4 0
3 years ago
Read 2 more answers
Leticia charges 8$ per hour to babysit. She babysat Friday night for 4 hours ,and then she babysat again on saturday.She earned
BaLLatris [955]
Leticia babysat on Saturday for 5 hours. She already babysat for 4 hours which makes it (8 x 4) =$32 But she earned $72 so the rest $40 / 8 =5 hours 
4 0
4 years ago
Which value represents the first two terms of the sequence a1=2 and an=-3(an-1)^2?
satela [25.4K]
I'm not really sure what you're asking, but if you want to calculate the first two terms of the sequence after a1, then here's the answer:
If a1=2, then a2 = -3(a1 - 1)^2 = -3(2-1)^2 = -3*(-1)^2 = -3*1 = -3.
Then, a3 = -3(a2 - 1)^2 = -3(-3-1)^2 = -3(-4)^2 = -3*16 = -48.
I'm sorry if this is not what you wanted.
8 0
3 years ago
If a || b, m∠2 = 63°, and m∠9 = 105°, find the measure of each missing angle.
Ne4ueva [31]

Given that a || b, m∠2 = 63° and m∠9 = 105°.

Now, all the angles are as follows:

m∠5= m∠2 = 63° [vertically opposite angle]

m∠7= m∠9=105° [vertically opposite angle]

m∠8= 180°-m∠9=180°-105°=75° [Supplementry angles, m∠8+m∠9=180°]

m∠10= m∠8= 180° [vertically opposite angle]

m∠6= m∠8=75° [ Alternate angles]

m∠3= m∠6=75° [vertically opposite angle]

m∠1= 180°-(m∠2+m∠3)=180°-(63°+75°)=42° [as m∠1+m∠2+m∠3=180°]

m∠4= m∠1=42° [vertically opposite angle]

m∠11=m∠4=42° [ Alternate angles]

m∠13= m∠11=42° [vertically opposite angle]

m∠12= 180°-m∠11=180°-42°=138° [as m∠8+m∠9=180°]

m∠14 = m∠12=138° [vertically opposite angle]

4 0
3 years ago
Temperature in degrees Fahrenheit is equal to 32 more than 9/5 times the temperature in degrees Celsius . One day the high tempe
bazaltina [42]

The high temperature is 35 degree celsius

<em><u>Solution:</u></em>

Given that, Temperature in degrees Fahrenheit is equal to 32 more than 9/5 times the temperature in degrees Celsius

Let "f" be the temperature in degree Fahrenheit

Let "c" be the temperature in degree celsius

Therefore,

Temperature in degrees Fahrenheit = 32 + \frac{9}{5} times the temperature in degrees Celsius

f = 32 + \frac{9}{5} \times c

One day the high temperature in Edison. Nj was 95 degrees Fahrenheit

f = 95 ; c = ?

Substitute f = 95 in above equation

95 = 32 + \frac{9c}{5}\\\\95=\frac{32 \times 5 +9c}{5}\\\\95 \times 5 = 160+9c\\\\475 = 160 + 9c\\\\9c = 475 - 160\\\\9c = 315\\\\c = 35

Thus high temperature in degrees Celsius is 35 degree celsius

5 0
3 years ago
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