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uranmaximum [27]
3 years ago
6

Find the value of the spring constant for the spring in Trial I. Use 0.367 s for the value of the period. The mass of the suspen

ded block is 0.400 kg.
Physics
1 answer:
Agata [3.3K]3 years ago
8 0

Answer:

117.28 N/m

Explanation:

step one:

given

Period T= 0.367s

mass m= 0.4kg

Required

the spring constant k

Step two:

The expression for the period, mass and spring constant relation is

T=2π√m/k

making k subject of the formula

T/2 \pi = \sqrt m/k

square both sides

(T/2 \pi)^2= m/k

k= m/(T/2 \pi)^2

k=0.4/(0.367/2*3.142)^2

k=0.4/(0.05840)^2

k=0.4/0.0034105\\\\k=117.28 N/m

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\begin{equation*} 333.33\text{ yds} \end{equation*}

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Two lasers are shining on a double slit, with slit separation d. Laser 1 has a wavelength of d/20, whereas laser 2 has a wavelen
Marta_Voda [28]

Answer:

a) that laser 1 has the first interference closer to the central maximum

c) Δy = 0.64 m

Explanation:

The interference phenomenon is described by the expression

         d sin θ = m λ

Where d is the separation of the slits, λ the wavelength and m an integer that indicates the order of interference

For the separation of the lines we use trigonometry

        tan θ = sin θ / cos θ = y / x

In interference experiments the angle is very small

          tan θ = sin θ = y / x

         d y / x = m λ

a) and b) We apply the equation to the first laser

          λ = d / 20

          d y / x = m d / 20

          y = m x / 20

          y = 1 4.80 / 20

          y = 0.24 m

The second laser

        λ = d / 15

          d y / x = m d / 15

          y = m x / 15

          y = 0.32 m

We can see that laser 1 has the first interference closer to the central maximum

c) laser 1

They ask us for the second maximum m = 2

            y₂ = 2 4.8 / 20

            y₂ = 0.48 m

For laser 2 they ask us for the third minimum m = 3

In this case to have a minimum we must add half wavelength

         y₃ = (m + ½) x / 15

         m = 3

         y₃ = (3 + ½) 4.8 / 15

         y₃ = 1.12 m

        Δy = 1.12 - 0.48

        Δy = 0.64 m

4 0
3 years ago
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