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uranmaximum [27]

3 years ago

6

Find the value of the spring constant for the spring in Trial I. Use 0.367 s for the value of the period. The mass of the suspen

ded block is 0.400 kg.

1 answer:

Agata [3.3K]3 years ago

8 0

Answer:

117.28 N/m

Explanation:

step one:

given

Period T= 0.367s

mass m= 0.4kg

Required

the spring constant k

Step two:

The expression for the period, mass and spring constant relation is

T=2π√m/k

making k subject of the formula

$T/2 \pi = \sqrt m/k$

square both sides

$(T/2 \pi)^2= m/k$

$k= m/(T/2 \pi)^2$

$k=0.4/(0.367/2*3.142)^2$

$k=0.4/(0.05840)^2$

$k=0.4/0.0034105\\\\k=117.28 N/m$

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(a) $-1.5\cdot 10^6 N$

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Solving for a,

$a=\frac{v^2-u^2}{2d}=\frac{0-20.0^2}{2(0.01)}=-20000 m/s^2$

And the average force on the person is given by

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b) $-1.0\cdot 10^5 N$

In this case,

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a is the acceleration

d = 15.00 cm = 0.15 m is the displacement of the person with the air bag

So the acceleration is

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4 years ago

Light passes through a 0.15 mm-wide slit and forms a diffraction pattern on a screen 1.25 m behind the slit. The width of the ce

Elena L [17]

Answer:

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Explanation:

From the question we are told that

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Generally the width of the central maximum is mathematically represented as

$y = \frac{m * D * \lambda}{a}$

Here m is the order of the fringe and given that we are considering the central maximum, the order will be m = 1 because the with of the central maximum separate's the and first maxima

So

$\lambda = \frac{a y}{ m * D }$

=> $\lambda = \frac{ 0.000015 * 0.0075}{ 1 * 1.2 }$

=> $\lambda = 900 *10^{-9} \ m$

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6 0

3 years ago

1 What conclusion can you draw about semicircular canals from their name ? A Their shape B Their size Their location in your bod

oee [108]

Answer:

A. Their shape

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Sometimes scientists make a mistake, or ___, and need to do the experiment again?

Vlad1618 [11]

Sometimes scientists make a mistake or Miscalculate and need to do the experiment again.

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3 years ago

A drum rotates around its central axis at an angular velocity of 19.8 rad/s. If the drum then slows at a constant rate of 3.02 r

Debora [2.8K]

a) Time taken =6.39 s

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<u>Explanation:</u>

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b.) we know that

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3 0

4 years ago