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Phoenix [80]
3 years ago
6

Sometimes scientists make a mistake, or ___, and need to do the experiment again?

Physics
1 answer:
Vlad1618 [11]3 years ago
5 0
Sometimes scientists make a mistake or Miscalculate and need to do the experiment again. 
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A loop of wire is placed in a magnetic field such that it has a flux, LaTeX: \phi ϕ, through it. The loop is compressed so that
Juliette [100K]

Answer:

B'= 3.333 B

Explanation:

Lets take

Initial area = A

Magnetic field = B

The area after compression

A'=0.3 A

Magnetic field = B'

We know that flux ,Ф

Ф = B A

Given that flux is constant so

B A = B' A'

B A=B' x 0.3 A

B'= 3.333 B

It means that magnetic field will increase.

6 0
3 years ago
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Why does the earth orbit the sun for 1 month
VikaD [51]
The Earth orbits the sun constantly, continuously, and all the time.  " 24/7/365 "

From the sun's point of view, it takes the Earth roughly 365 and 1/4 days
to make the complete trip, all the way around one time.  That's the length
of time that we call "one year".

When you talk about orbiting in one month, you're thinking of the moon
orbiting the Earth. THAT length of time is about 27.32 days.
3 0
4 years ago
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A 4.0 kg mass is attached to a spring whose spring constant is 950 N/m. It oscillates with an amplitude of 0.12 m. What is the m
Fudgin [204]

Answer:

velocity = 2.62m/s

Explanation:

950= (4 x A)/0.12

950 x 0.12 = 4 x A

114 = 4 x A

A = 114/4

A = 28.5m/s²

  • U²=2as
  • U² = 2 x 28.5 x 0.12
  • U² = 6.84
  • U = √6.84
  • U = 2.62m/s
3 0
3 years ago
As a compass finds the northern direction which of the following is it aligning with
Anna [14]
It would be aligning with the north pole. 
8 0
4 years ago
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A copper rod has a length of 1.7 m and a cross-sectional area of 3.6 10-4 m2. One end of the rod is in contact with boiling wate
Lina20 [59]

Answer:

Mass of ice per second melt is 2.74×10^-5Kg/s

Explanation:

Temperature of one end of the copper rod is 100°C boiling point of water and the other end of the rod is 0°C

Temperature difference in the copper rod = 100 - 0 = 100°C

Cross sectional area = 3.6×10^-4m^2

Length of rod , L = 1.7m

Amount of heat transfer from the boiling water to the ice water mix through the copper rod is given by:

Q = KA◇T/ L

Q = (390×(3.6×10^-4)×100°C)/1.7

Q = 14.04/1.7

Q = 8.26J/s

From the equation

Q = mLf

m = Q/ Lf

Where Lf = Latent heat of fusion for water= 3.34×10^5J/Kg

m = 8.26/(3.34×10^5)

m = 2.74×10^-5Kg/s

3 0
3 years ago
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