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2 years ago

Help please thank you whoever helps

Physics

1 answer:

Delicious77 [7]2 years ago

8 0

Answer:

24a. WX, XW

24b. XY

24c. WV

24d. UV, VU

24e. XY, YX

24f. YX

24g. VW

24h. YZ, ZY

24i. VW, WV

24j. WX

25a. ≈ 20°C

25b. ≈ 290°C

25c. ≈ 20°C

25d. ≈ 290°C

Explanation:

Let's look at the graph and see what phase changes happen as we go from U to Z.

UV: the substance is a solid. As heat is added, temperature increases.

VW: the solid begins to melt. The temperature stays constant as the combination of solid and liquid becomes more and more liquid.

WX: the solid is done melting, and there's only liquid now. As heat is added, temperature increases.

XY: the liquid begins to boil. The temperature stays constant as the combination of liquid and gas becomes more and more gas.

YZ: the liquid is done boiling, and there's only gas now. As heat is added, temperature increases.

If we reverse the direction, YX represents condensation instead of boiling, and WV represents freezing instead of melting.

Kinetic energy of molecules increases with temperature. The greatest increase in temperature is also the greatest increase in kinetic energy.

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Answer:

A water strider can walk along the surface of earth due to the surface tension of water. 

Explanation:

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2 years ago

What is the frequency of a radio wave with an energy of 3.686 × 10−24 j/photon?answer in units of hz?

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To solve this problem, we have to use the formula:

E = h f

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3 years ago

A car of mass M = 1000 kg traveling at 50.0 km/hour enters a banked turn covered with ice. The road is banked at an angle θ , an

kupik [55]

The radius of the curved road at the given condition is 54.1 m.

The given parameters:

mass of the car, m = 1000 kg
speed of the car, v = 50 km/h = 13.89 m/s
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The normal force on the car due to banking curve is calculated as follows;

$Fcos(\theta) = mg$

The horizontal force on the car due to the banking curve is calculated as follows;

$Fsin(\theta) = \frac{mv^2}{r}$

Divide the second equation by the first;

$\frac{Fsin(\theta)}{Fcos(\theta) } = \frac{mv^2}{rmg} \\\\tan(\theta) = \frac{v^2}{rg} \\\\r = \frac{v^2}{g \times tan(\theta)} \\\\r = \frac{13.89^2}{9.8 \times tan(20)} \\\\r = 54.1 \ m$

Thus, the radius of the curved road at the given condition is 54.1 m.

Learn more about banking angle here: brainly.com/question/8169892

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2 years ago

Suzy drops a rock from the roof of her house. Mary sees the rock pass her 2.7 m tall window in 0.129 sec. From how high above th

vladimir1956 [14]

Answer:

h = 22.35 m

Explanation:

given,

initial speed of the rock,u = 0 m/s

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2 years ago

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The answer is B.

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Hope it helps!

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3 years ago