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SashulF [63]
3 years ago
13

A star with a mass like the Sun which will soon die is observed to be surrounded by a large amount of dust and gas -- all materi

al it has expelled in the late stages of its life. If astronomers want to observe the radiation from such a giant star surrounded by its own debris, which of the following bands of the spectrum would be the best to use to observe it?
a. gamma-rays
b. x-rays
c. ultraviolet
d. infrared
e. very long wavelength radio waves
Physics
1 answer:
Dafna11 [192]3 years ago
5 0

Answer: D. Infrared

Infrared is the best way to observe it.

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how long does it take a car to accelerate from 3.4m/s to 20.9m/s if the average acceleration is 6.0m/s (squared).
Gre4nikov [31]

Average acceleration is the ratio of the change in velocity to the time it takes for that change to occur:

a_{\mathrm{av}}=\dfrac{\Delta v}{\Delta t}

We want to find \Delta t:

6.0\,\dfrac{\mathrm m}{\mathrm s^2}=\dfrac{20.9\,\frac{\mathrm m}{\mathrm s}-3.4\,\frac{\mathrm m}{\mathrm s}}{\Delta t}

\implies\Delta t=2.9\,\mathrm s

4 0
3 years ago
In a cathode ray tube, the number of electrons that reach the fluorescent screen is controlled by the:
EleoNora [17]

Answer:

Grid

Explanation:

The number of electrons attaining the fluorescent light is regulated by the grid in a cathode ray tube.When the heater is supplied with current, it allows the electrons to emit from the cathode. Before approaching the anode the electrons pass through grid opening. The number of electrons attempting to reach the anode may also be regulated by managing the number of electrons passing through the grid.

6 0
3 years ago
What would u expect the tides to be like during a first quarter moon?
kicyunya [14]

Answer:

During the first quarter or last quarter phase of the moon, when the sun and moon are perpendicular (at right angles) to each other in relation to the Earth, the tidal gravitational pulls interfere with each other, producing weaker tides, known as neap tides.

Explanation:

3 0
3 years ago
Read 2 more answers
Leash a block of 0.5 kg down the entire length of an inclined plane forming a name of 37 ° with the horizontal. Friction with th
castortr0y [4]
The potential energy of the block is given by:
V = m*g*h
m mass
g = 9.81m/s²
h height

The potential energy of a spring is given by:
V = 0.5 * k * x²

k spring constant
x compression of the spring

If the block starts from rest it has potential energy, but no kinetic energy. As it slides down the incline potential energy is converted into kinetic energy. When the block hits the spring the kinetic energy is converted into spring's potential energy. If the spring is fully compressed and the block is at rest again, the block has transferred all its energy into the spring. No energy is lost. So we can write:

m * g * h = 0.5 * k * x²

m = 0.5 kg
g = 9.81 m/s²
h = 2.5m * sin 37° = 1,5 m
x = 0,6 m

Solve for k.

k = 2 * m * g * h / x² = 40.8 N/m
6 0
3 years ago
A machinist turns the power on to a grinding wheel, at rest, at time t = 0 s. The wheel accelerates uniformly for 10 s and reach
Nookie1986 [14]

Answer:489 Revolutions

Explanation:

Given

Angular deceleration(\alpha ) =1.5rad/s^2

Given wheel angular velocity =96 rad/s when machine is turned off

time taken by machine to reach zero angular velocity

0=\omega _0+(\alpha)t

0=96+(-1.5)t

t=64 sec

angular displacement is given by

\theta =\omega_0t+\frac{1}{2}\alpha t^2

\theta =96(64)-\frac{1}{2}(-1.5)(64^2)=3072 degree

For revolutions =\frac{3072}{2\cdot \pi}=488.86 \approx 489 revolution during Slowdown

5 0
3 years ago
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