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SashulF [63]
2 years ago
13

A star with a mass like the Sun which will soon die is observed to be surrounded by a large amount of dust and gas -- all materi

al it has expelled in the late stages of its life. If astronomers want to observe the radiation from such a giant star surrounded by its own debris, which of the following bands of the spectrum would be the best to use to observe it?
a. gamma-rays
b. x-rays
c. ultraviolet
d. infrared
e. very long wavelength radio waves
Physics
1 answer:
Dafna11 [192]2 years ago
5 0

Answer: D. Infrared

Infrared is the best way to observe it.

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Can anybody answer this its a science question NO LINKS !!!!
Zigmanuir [339]

Answer:

1) Potential energy (gravitation)

2)Potential energy

3)Kinetic energy

4) Kinetic energy

5)Potential energy

6)Kinectic energy

7)Potential energy (elastic)

Hope it helps

8 0
3 years ago
Some of the largest volcanoes in the solar system are on mars. The most likely explanation is that mars
ivolga24 [154]

Answer: Mars has lower gravity and lower magma buoyancy

Explanation: The gravity in mars is low. Low gravity affect the occurrence of volcanic eruptions. The buoyancy of the magma in Mars is lower and the depth of the magma chamber deeper (Buoyancy is the difference in density between the surrounding crust and the magma ascending for eruption). Olympus Mons which is larger and wider than mount Everest was formed as a result of overcoming of the low gravity and buoyancy by the magma to release enormous volume of magma to the surface.

Another reason why the volcanoes on Mars are so large is because the crust on Mars is static unlike Earth.

4 0
3 years ago
QUIK!!!!!!!!!!!!! 1. Compare your scores to your partner’s scores. Explain the reason for any differences. 2. How can improving
kvv77 [185]
2.Improving my balance and coordination can affect my performance in sports or recreational activities by planing better in activities also <span>improving my speed. My activities all need skills that I am really good at.
3.</span>The activity that was most difficult for me to perform was the Stork Stance test because I am not good with balancing and that is something <span>I need to improve.
4.</span>An activity that could help improve my striking and my reaction time.
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6 0
3 years ago
Suppose you are in an elevator that is moving upward with a constant velocity. A scale inside the elevator shows your weight to
Ulleksa [173]

Answer:

a) Less than 600 N

b) 600 N

c) Less than 600 N

Explanation:

The value registered by the scale, measures the normal force on the object placed on the scale.

The person on the scale, is acted by two external forces, gravity (which we call weight, and always go downward) and the normal force, an upward force in this case.

The difference between both forces, according Newton’s 2nd law, must be equal to the product of the mass of the object, times the acceleration.

If the elevator moves upward to a constant speed, and then slows down, this means that there exists a net force on the person, producing a acceleration directed downwards on him.

If we take the direction of the acceleration (downward) to be positive, this means that the difference between gravity force and normal force must be positive.

As mg = 600 N (equal to normal force when no net force is present), the normal force in this case must be less than 600 N.

b) If the elevator is stopped, the effect is the same like it were moving at constant speed, so in this case the normal force remains the same: 600 N

c) Assuming that it starts from rest, if it accelerates going downward, and if we take as positive the downward direction, in order to satisfy Newton’s 2nd Law, normal force must be less than 600N so the difference between gravity and normal force remain positive.

4 0
3 years ago
the car starts from rest at s=0 and increases its speed at at=4m/s^2. Determine the time when the magnitude of acceleration beco
dem82 [27]

Answer:

<em>Time =  5 seconds</em>

<em>Distance = 50 meters</em>

Explanation:

<u>Constantly Accelerated Motion</u>

When the velocity of a moving object changes at a constant rate, called acceleration, the velocity changes in same amounts in the same times. The question has a mistake when asking when the acceleration is 20 m/s. If the acceleration is constant, the only variable that can change to that value is the velocity. The equation to calculate the speed is

v_f=v_o+a.t

And the distance s is

\displaystyle s=v_o.t+\frac{gt^2}{2}

Given the object starts from rest, vo=0 and vf=20 m/s at a=4\ m/s^2. We compute t

\displaystyle t=\frac{v_f-v_o}{a}=\frac{20-0}{4}

\boxed{t=5\ sec}

Now we compute s

\displaystyle s=0+\frac{4\times 5^2}{2}

\boxed{s=50\ m}

5 0
3 years ago
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