There is an infinite number of values that are in both the domain and range.
<h3>Define domain and range.</h3>
The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the collection of values it can take as input. After we enter an x value, the function outputs this sequence of values. The collection of all potential inputs for a function is its domain.
Given Data
Range of a function in the form f(x) = m√x, where m is a real number greater than 0
There is an infinite number of values that are in both the domain and range.
The range of a function always has an unlimited number of values when the domain of the function does. The claim is untrue because more than one input and output might have been matched.
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Answer: a. 0.14085
b. 3.826 x 
c. 0.5437
d. 0.0811
Step-by-step explanation:
Given average amount parents and children spent per child on back-to-school clothes in Autumn 2010 , 
= $527
Given standard deviation , 
= $160
Let X = amount spent on a randomly selected child
Also Z = 
a. Probability(X>$700) = P( > 
) = P(Z>1.08125) = 0.14085 {Using Z % table}
b. P(X<100) = P( Z < 
) = P(Z< -2.66875) = P(Z > 2.66875) = 3.826 x
c. P(450<X<700) = P(X<700) - P(X<=450)
P(X<700) = 1 - P(X>=700) = 1 - 0.14085 = 0.8592
P(X<=450) = P(Z<= 
) = P(Z<= -0.48125) = P(Z<=0.48125) = 0.3155
So final P(450<X<700) = 0.8592 - 0.3155 = 0.5437
d. P(X<=300) = P(Z<= 
) = P(Z<= -1.4188) = P(Z>=1.4188) = 0.0811
All the above probabilities are calculated using Z % table along with interpolation between two values.
Answer and Step-by-step explanation:
A Quarter is equal to 25 cents.
A Nickel is equal to 5 cents.
We have 4 quarters and 8 nickels, so times this amount of coins to their values.
4 × 25 = 100
8 × 5 = 40
Now, we add these together.
140.
This is 140 cents.
After the 100 mark, it turns into a dollar (because there is 100 pennies (cents) in 1 dollar).
So that means the total amount of money we have is One dollar and Forty cents ($1.40)
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The first thing we must do for this case is to define a variable:
x: number of years
y: total salary
We have then:
For first company:
y = 1500x + 31000
For second company:
y = 2000x + 28500
Equaling both equations we have:
1500x + 31000 = 2000x + 28500
Clearing x:
2000x - 1500x = 31000 - 28500
500x = 2500
x = 2500/500
x = 5
Answer:
It will take for the salaries to be the same about:
x = 5 years
