The solution would be like this for this specific problem:
H0: p = p0, or <span>
H0: p ≥ p0, or
H0: p ≤ p0 </span>
find the test statistic z
= (pHat - p0) / sqrt(p0 * (1-p0) / n)
where pHat = X / n
The p-value of the test is
the area under the normal curve that is in agreement with the alternate
hypothesis. <span>
H1: p ≠ p0; p-value is the area in the tails greater than |z|
H1: p < p0; p-value is the area to the left of z
H1: p > p0; p-value is the area to the right of z </span>
Hypothesis equation:
H0: p ≥ 0.67 vs. H1: p
< 0.67
The test statistic is: <span>
z = ( 0.5526316 - 0.67 ) / ( √ ( 0.67 * (1 - 0.67 ) / 38 )
z = -1.538681 </span>
The p-value = P( Z < z
) <span>
= P( Z < -1.538681 )
<span>= 0.0619</span></span>
Answer:
First, these angles are alternate interior angles.


Step-by-step explanation:
(10x - 5)° and (9x + 1)° are alternate interior angles. Thus, they are congruent to each other.
Thus, to find x, we will set each angle equal to the other.

Solve for x. Collect like terms


Answer:

Step-by-step explanation:
(a/5) - (b/3) = (a/2) - (b/6)
+(B/3) + (b/3)
NOTE: use property of equality to isolate <em>b</em> from <em>a</em>
(a/5) = (b/3) + (a/2) - (b/6)
-(a/2) - (a/2)
NOTE: continue to use property of equality to isolate <em>a</em><em> </em>from <em>b</em>
(a/5) - (a/2) = (b/3) - (b/6)
60((a/5) - (a/2)) = ((b/3) - (b/6))60
NOTE: 60 is a common multiple of 5, 2, 3, and 6
12a - 30a = 20b - 10b
NOTE: combine alike terms
-17a = 10b
-17a/-17 = 10b/-17
NOTE: decide by -16 to find what a is equal to

Final answer
is there any instructions above the circle?