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weqwewe [10]
3 years ago
10

5.

Mathematics
1 answer:
a_sh-v [17]3 years ago
4 0

Answer:

40 children went on the cruise.

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of adults on the cruise

y is the number of children on the cruise.

57 tickets were sold:

This means that x + y = 57, and since we want the number of children y, x = 57 - y

Each adult had to pay $22 for the cruise and each child had to pay $10. The company's total receipts were $774.

This means that:

22x + 10y = 774

Since x = 57 - y

22(57 - y) + 10y = 774

1254 - 22y + 10y = 774

12y = 480

y = \frac{480}{12}

y = 40

40 children went on the cruise.

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The function f determines the cost (in dollars) of a new Honda Accord in terms of the number of years t since 2000. That is, f (
xenn [34]

Complete  Question

The function f determines the cost (in dollars) of a new Honda Accord in terms of the number of years t since 2000. That is, f ( t ) represents the cost (in dollars) of a new Honda Accord t years after 2000. Use function notation to represent each of the following. The cost (in dollars) of a new Accord in 2006?

A. How much more a new Accord costs in 2013 as compared to the cost of a new Accord in 2010?

B. A new Accord in 2013 is how many times as expensive as a new Accord in 2010?

C. In  2016 , some cars cost  $980 more than the cost of a new Accord.How much does the other cars cost (in dollars)in 2016?

Answer:

a

     The cost of  a new Accord in 2013 compared to 2010 is  z  =  f(13) -  f(10)

b

   The magnitude at which the cost of   a new Accord in 2013 is greater          than the cost in 2010 is  

          x =  \frac{f(13)}{f(10)}

c

    The cost of the other cars is 2016 is   r  =  980 + f(16)

Step-by-step explanation:

From the question we are told that

     The cost (in dollars) of a new Honda Accord is  f(t)

       Where t is  number of years after 2000

The cost of the  Honda Accord at 2013 is  

        f(2013 - 2000) =  f(13)

The cost of the  Honda Accord at 2010 is  

        f(2010 - 2000) =  f(10)

So the cost difference between 2013 and 2010 is mathematically evaluated as

         z  =  f(13) -  f(10)

Let constant at which the cost of Honda Accord in 2013 is greater than its cost at 2010 be  x

So

      f(13) =  x f(10)

=>      x =  \frac{f(13)}{f(10)}

  The cost of the Honda Accord in 2016 is mathematically evaluated as

          f(2016 - 2000) =   f(16)    

Now the cost of these other cars is  mathematically evaluated as  

         r  =  980 + f(16)

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3 years ago
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