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3 years ago

Which statement describes the translation from the graph y=|x| to the graph y=|x+3|-4?

Mathematics

1 answer:

Pavel [41]3 years ago

8 0

Answer:

B) shift 3 units left and 4 units down

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crimeas [40]

Answer: The domain has to be x and the range y. But for independent and dependent variable I can't help. So srry. The picture doesn't show the work. Have a nice day :)

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3 years ago

What is the answer to dis equationn 6+9+6+9+6+9=???

jonny [76]

Answer:

Step-by-step explanation:

6 × 3 = 18

9 × 3 = 27

18 + 27 = 45

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4 years ago

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I will mark as brainliest please i am newbie in 12

Vaselesa [24]

Answer:

I can't see the pic

Step-by-step explanation:

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3 years ago

A jewelry salesperson earns 6two fifths ?% commission on all sales. Today she sold ?$5 comma 570 in jewelry. What is her total c

Free_Kalibri [48]

Answer:

$356.48

Step-by-step explanation:

We have been given that a jewelry salesperson earns $6\frac{2}{5}$ % commission on all sales. Today she sold $5,570 in jewelry.

To find the total commission earned by salesperson is same as finding the $6\frac{2}{5}$ % of 5,570.

Let us convert $6\frac{2}{5}$ in decimal form.

$6\frac{2}{5}=6.4$

$\text{Total commission earned by salesperson}=\frac{6.4}{100}\times 5,570$

$\text{Total commission earned by salesperson}=0.064\times 5,570$

$\text{Total commission earned by salesperson}=356.48$

Therefore, the total commission earned by salesperson is $356.48.

4 0

3 years ago

Rationalise:<br>(1) 4/(2+root3+root7)<br>(2) 4/(2root3+root5)

Temka [501]

$\frac{4}{2+\sqrt3+\sqrt7}\cdot\frac{2-(\sqrt3+\sqrt7)}{2-(\sqrt3+\sqrt7)}=\frac{8-4\sqrt3-4\sqrt7}{2^2-(\sqrt3+\sqrt7)^2}=\frac{8-4\sqrt3-4\sqrt7}{4-3-2\sqrt{3\cdot7}-7}\\\\=\frac{8-4\sqrt3-4\sqrt7}{-6-2\sqrt{21}}=\frac{-2(2\sqrt3+2\sqrt7-4)}{-2(3+\sqrt{21})}=\frac{2\sqrt3+2\sqrt7-4}{3+\sqrt{21}}\cdot\frac{3-\sqrt{21}}{3-\sqrt{21}}\\\\=\frac{6\sqrt3-2\sqrt{63}+6\sqrt7-2\sqrt{147}-12+4\sqrt{21}}{3^2-(\sqrt{21})^2}=\frac{6\sqrt3-2\sqrt{9\cdot7}+6\sqrt7-2\sqrt{49\cdot3}-12+4\sqrt{21}}{9-21}$

$=\frac{6\sqrt3-6\sqrt7+6\sqrt7-14\sqrt3-12+4\sqrt{21}}{-12}=\frac{-8\sqrt3+4\sqrt{21}-12}{-12}=\frac{-4(2\sqrt3-\sqrt{21}+3)}{-12}\\\\=\frac{2\sqrt3-\sqrt{21}+3}{3}$

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$\frac{4}{2\sqrt3+\sqrt5}\cdot\frac{2\sqrt3-\sqrt5}{2\sqrt3-\sqrt5}=\frac{8\sqrt3-4\sqrt5}{(2\sqrt3)^2-(\sqrt5)^2}=\frac{8\sqrt3-4\sqrt5}{4\cdot3-5}=\frac{8\sqrt3-4\sqrt5}{12-5}\\\\=\frac{8\sqrt3-4\sqrt5}{7}$

4 0

4 years ago

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