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givi [52]
3 years ago
5

Find the average rate of change for the given function from x = −2 to x = 1.

Mathematics
1 answer:
egoroff_w [7]3 years ago
4 0
1......................................
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Step-by-step explanation:

can i have branliest?

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Which of the following comparisons is true? 24,762 = 24,662 335,989 > 335,998 454,909 887,012
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454,909 < 887,012 <===
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Yo can someone help me out
VMariaS [17]

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About 13​% of the population of a large country is nervous around strangersnervous around strangers. If two people are randomly​
Molodets [167]

Answer:

1.69% probability both are nervous around strangers.

24.31% probability at least one is nervous around strangers.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are nervous around strangers, or they are not. The people are chosen randomly, which means that the probability of a person being nervous around strangers is independent from other people. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

About 13​% of the population of a large country is nervous around strangers.

This means that p = 0.13.

Two people are randomly​ selected

This means that n = 2.

What is the probability both are nervous around strangers?

This is P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169

1.69% probability both are nervous around strangers.

What is the probability at least one is nervous around strangersnervous around strangers?

This is P(X \geq 1)

P(X \geq 1) = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.13)^{1}.(0.87)^{1} = 0.2262

P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169

P(X \geq 1) = P(X = 1) + P(X = 2) = 0.2262 + 0.0169 = 0.2431

24.31% probability at least one is nervous around strangers.

3 0
3 years ago
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Thepotemich [5.8K]

Answer:

  5.  The initial value corresponds to the y value when x = 0.

Step-by-step explanation:

You are given the graph, so you do not need to plot anything. Finding rise over run does nothing to help you find the initial value.

The "initial value" on a graph of a linear function is also known as the "y-intercept." It is the y-value corresponding to x = 0.

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