Answer:
TQ = 10
Step-by-step explanation:
The diagonal divides the square into 2 right triangles with the diagonal being the hypotenuse.
Using Pythagoras' identity in triangle TPQ
TQ² = PQ² + PT²
TQ² = 10² + 10² = 100 + 100 = 200 ( take square root of both sides )
TQ =
=
=
×
= 10
So, the subtraction looks like this:
223
-119
_______
The reason why combining place values here is necessary is that 3 is less than 9 (so I can't just substract in the one's place without going to negative numbers)
so we combine the ones and tens places and substract the whole: 23-19 is four!
223
-119
_______
04
and then we continue
223
-119
_______
204
and that's the result!
Answer:
12 picks total
Step-by-step explanation:
1. multiply 2 (orange picks) by 4 (green picks)
2*4=8 total orange picks
2. add green picks (4) + orange picks (8)
4+8=12
Answer:
"Donna loaned $30 to her brother. He then paid her back $30 the next day" is the correct situation
Answer:
- r(0) = <0, 100> . . . . . . . .meters
- r'(0) = <7.071, 7.071> . . . . meters per second
Step-by-step explanation:
<u>Initial Position</u>
The problem statement tells us we're measuring position from the ground at the base of the building where the projectile was launched. The initial horizontal position is presumed to be zero. The initial vertical position is said to be 100 meters from the ground, so (in meters) ...
r(0) = <0, 100>
<u>Initial Velocity</u>
The velocity vector resolves into components in the horizontal direction and the vertical direction. For angle α from the horizontal, the horizontal component of velocity is v₁·cos(α), and the vertical component is v₁·sin(α). For v₁ = 10 m/s and α = π/4, the initial velocity vector (in m/s) is ...
r'(0) = <10·cos(π/4), 10·sin(π/4)>
r'(0) ≈ <7.071, 7.071>