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3 years ago

A circle has a diameter with endpoints at (0, 4) and (0, –8). What is the approximate area of the circle?

Mathematics

2 answers:

Morgarella [4.7K]3 years ago

6 0

Answer:

$36\pi$

Step-by-step explanation:

The diameter is:

The Euclidean distance between points (x1, y1) and (x2, y2) is:

sqrt((x1 - x2)^2 + (y1 - y2)^2)

Substitute (x1, y1) = (0, 4) and (x2, y2) = (0, -8):

= sqrt((-0 + 0)^2 + (-(-8) + 4)^2)

= sqrt(12^2)

= 12

or simply:

diameter: 4-(-8)=12

The radius is:

12/2=6 units

The area of the circle:

$\pi r^2=\pi(6^2)=36\pi$

nadya68 [22]3 years ago

4 0

Answer:

113.04

Step-by-step explanation:

Area of a circle is πr2

π = 3.14

r = 6

πr2 = 113.04

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natulia [17]

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3 years ago

Divide the polynomial x^3+x^2-2x+3 by (x-1)

Anni [7]

Answer:

x² + 2x + (3 / (x − 1))

Step-by-step explanation:

Start by setting up the division:

.........____________

x − 1 | x³ + x² − 2x + 3

Start with the first term, x³. Divided by x, that's x². So:

.........____x²______

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Multiply x − 1 by x², subtract the result, and drop down the next term:

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x − 1 | x³ + x² − 2x + 3

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Repeat the process over again. First term is 2x². Divided by x is 2x. So:

.........____x² + 2x __

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

Multiply, subtract the result, and drop down the next term:

.........____x² + 2x __

x − 1 | x³ + x² − 2x + 3

.........-(x³ − x²)

...........----------

...................2x² − 2x

.................-(2x² − 2x)

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x doesn't divide into 3, so that's the remainder.

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8 0

3 years ago

Plzzz help I will give you 25 points

LuckyWell [14K]

Pretty sure the answer is 77

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2 years ago

Read 2 more answers

The height of the tunnel at the center is 35ft, and the vertical clearance must be 21 ft at a point of 8ft from the center. Find

Zinaida [17]

Answer:

y=-0.215x^2+35

Step by Step:

Let, $h=0$ , $k=35$ , $x=8$ , $y=21$

We know that, the general equation of the parabola.

$y-k = a(x-h)^2$

$\Rightarrow y=a(x-h)^2+k .........(i)$

Substitute the value of $h, k, x, y$ in equation $(i)$ and find the value of $a.$

$21=a(8-0)^2+35$

$\Rightarrow 21=a\times 8^2+35$

$\Rightarrow 21=64a+35$

$\Rightarrow 64a=21-35$

$\Rightarrow 64a=-14$

$\Rightarrow a=\frac{-14}{65}$

$\Rightarrow a=-0.215$

Hence, the equation of the parabola is:

$y=-0.215x^2+35$

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