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3 years ago

Train A leaves Paris and travels at a constant speed of 75 mph toward Pisa. At the

Mathematics

1 answer:

kolezko [41]3 years ago

5 0

Answer: $4.016\ hr$

Step-by-step explanation:

Given

Train A has speed of $v_a=75\ mph$

Train B has speed of $v_b=50\ mph$

If Paris and Pisa is 500 miles apart

If they meet x hours after the start

The sum of the distances traveled by Train A and B is 500 miles

$\Rightarrow 75\times x+50\times x=500\\\Rightarrow 125x=500\\\Rightarrow x=4.016\ hr$

So, after $4.016\ hr$ they will pass each other.

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The sample consisted of 50 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 25 day students,

bulgar [2K]

Answer: The test statistic is t= -0.90.

Step-by-step explanation:

Since we have given that

n₁ = 50

n₂ = 25

$\bar{x_1}=3.02\\\\\bar{x_2}=3.04\\\\\sigma_1=0.08\\\\\sigma_2=0.06$

So, s would be

$s=\sqrt{\dfrac{n_1\sigma_1^2+n_2\sigma_2^2}{n_1+n_2-2}}\\\\s=\sqrt{\dfrac{50\times 0.08^2+25\times 0.06^2}{50+25-2}}\\\\s=0.075$

So, the value of test statistic would be

$t=\dfrac{\bar{x_1}-\bar{x_2}}{s(\dfrac{1}{n_1}+\dfrac{1}{n_2})}\\t=\dfrac{3.02-3.04}{0.074(\dfrac{1}{50}+\dfrac{1}{25})}\\\\t=\dfrac{-0.04}{0.074(0.02+0.04)}\\\\t=\dfrac{-0.04}{0.044}\\\\t=-0.90$

Hence, the test statistic is t= -0.90.

7 0

3 years ago

I’m confused on how to find x. Can someone help me on this worksheet please ASAP!?

igor_vitrenko [27]

9514 1404 393

Answer:

x=2 (work is correct)
x=4
x=44
x=4
x=any number
impossible; no such number

Step-by-step explanation:

1. The equation is ...

3x +5 = 11

3x = 11 -5 = 6

x = 6/3 = 2 . . . . matches the work shown

2. The equation is ...

(x +2)·5 = 30

x +2 = 30/5 = 6

x = 6 -2 = 4

3. The equation is ...

(x/2) +2 = 24 . . . . matches the work shown

x/2 = 24 -2 = 22

x = 22·2 = 44

4. The equation is ...

2x +8 = x +12

2x = x + 12 -8 = x +4

2x -x = x -x +4

x = 4

5. The equation is ...

2x +4 -x -3 = x +1

x +1 = x +1 . . . . . true for any value of x

6. The equation is ...

(3x +6) -2x = x +3

x +6 = x +3 . . . . . not true for any number

_____

<em>Additional comment</em>

The work shown is correct. You find x by writing and solving an appropriate equation. To solve the equation, undo the steps that are done to x. Undo addition by adding the opposite. Undo multiplication by diving by the multiplier. It often helps to collect terms before you start the "undo" steps.

For x on both sides of the equation (as in problems 4–6), you can subtract the term with the lowest coefficient. (Of course, you must subtract it from both sides of the equation.) In problem 5, if you do that, you get 1=1, which is true for any value of x. In problem 6, if you do that, you get 6=3, a false equation, indicating no value of x will make it true.