35 has 4 divisors, hence two factor pairs: 1*35 and 5*7. Each corresponds to a set of perfect squares that differ by 35
One pair is ((35±1)/2)^2 = {17^2, 18^2} = {289, 324}
The other is ((7±5)/2)^2 = {1^2, 6^2} = {1, 36}
For this use the law of sines:
cross-multiply:
16×sin (J) = 11×0.97
sin(J) = 10.72/16
sin(J) = 0.67
hit the "arcsin" button on your calculator:
therefore answer B. 42 is the correct answer!!
Answer: (2,2), (4,2)
First, I subtracted 2y from both sides of the second equation. Then, I substituted -2y+6 in for x in the first equation (-2y+6)²+4y²=20. Then, I expanded 4y²-24y+16+4y²=20. Next, I combined like terms, and moved everything to one side 8y²-24y+16=0. Then, I factored out an 8, and then finished factoring 8(y-2)(y-1). This gives me my y-values, y=1,2. Next, I inserted each y-value into the second equation and got x=-2(1)+6 ---> x=4 (The first solution is (4,1). ) and x=-2(2)+6----->x=2 (The second solution is (2,2).
Answer:
Step-by-step explanation:
n = 3 => f(n) = -4*-3+8 = -44
n= 0 => f(n) = -4*0+8 = 8
n= 2 => f(n) = -4*2+8 = 0
n= 7 => f(n) = -4*7+8 = -20
Answer:
Step-by-step explanation:
1+1=2
