All categories

3 years ago

PLEASE HELP!!!!! 1-Suppose the population of a city is 50000 and growing 3% each year.

Mathematics

1 answer:

Hunter-Best [27]3 years ago

7 0

Answer:

A 104,689

Step-by-step explanation:

y= a x b^x

y=50,000 x 1.03^x

You might be interested in

HELPP PLEASE DUE I N 1 HOURRR

agasfer [191]

Answer:

i dont know the part one but

well 5% of 30 = 6

so that means it would be 6%

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

HELP ME WITH THIS PLS SIMPLIFY IT DONT SEND A LINK

Cloud [144]

Answer:

-.1

Step-by-step explanation:

First we do

19-1.67 since left to right

this is 2.3

then we multiply -2.4 with the + sign to get -2.4

then we add 2.3 to -2.4 to get -.1

5 0

3 years ago

Read 2 more answers

Please help me on this

Lisa [10]

B or (0,-2) is the answer i would go with

5 0

3 years ago

Read 2 more answers

The 4-inch radius pizza for $3 or the 8-inch radius pizza for $14. 112

omeli [17]

Buy how many ever u want of the 4 inch it is a better deal

4 0

3 years ago

Aria paid $75,000 for her house. Its property value increased by 2.2% per year. When Aria sold her house after eleven years, how

astra-53 [7]

Answer:

When Aria sold her house after eleven years it worth was $95,300.

Step-by-step explanation:

Given:

Aria paid $75,000 for her house. Its property value increased by 2.2% per year.

Now, to find the worth of Aria house when sold after eleven years.

Let the amount of house after eleven years be $x.$

Amount Aria paid for her house (A) = $75,000.

Rate of property increased per year (r) = 2.2%.

Time (t) = 11 years.

Now, to get the amount of house after eleven years we put formula:

$x=A\times (1+\frac{r}{100})^{11}$

$x=75000\times (1+\frac{2.2}{100})^{11}$

$x=75000\times (1+0.022)^{11}$

$x=75000\times (1.022)^{11}$

$x=75000\times 1.2704$

$x=95280.$

The amount of house after eleven years to the nearest hundred dollars is $95,300.

Therefore, when Aria sold her house after eleven years it worth was $95,300.

3 0

3 years ago