1. No answer ( may be due to incorrect question)
2. x = -3
y = 4
3. x= 4
y = 2
4.x = -63/40
y= -19/20
Step 1
Multiply equation 1 by the coefficient of x in equation 2
Multiply equation 2 by the coefficient of x I'm equation 1
(after completing this step you will derive equation 3 and 4 )
Step 2
Subtract equation 4 from equation 3
Step 3
Divide both sides of the equation by the coefficient of y
Step 4
substitute your value for y in equation 1 or 2
(after this you will derive the values of x)
Note : This method is for the Elimination of x
I hope it helps
Answer:
y=12x-16
Step-by-step explanation:
y-y1=m(x-x1)
y-20=12(x-3)
y=12x-36+20
y=12x-16
<span>x^2+10x + 25 = (x + 5)^2
missing = 25
hope it helps</span>
-11, -1, -8 that is all of what y would =
The common point between y = 2x + 5 and y = (1/2)x + 6 will have the same values for x and y.
Therefore, set the two y expressions equal to obtain
2x + 5 = (1/2)x + 6
Subtract (1/2)x from each side.
(3/2)x + 5 = 6
Subtract 5 from each side.
(3/2)x = 1
Multiply each side by 2/3.
x = 2/3.
From the first equation, obtain
y = 2*(2/3) + 5 = 19/3.
The common point is (2/3, 19/3). It is not equal to (3, 1/2).
Answer: False
