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3 years ago

Can you guys help me pls

Mathematics

1 answer:

Assoli18 [71]3 years ago

6 0

Answer:

D. (4 1/2, 2 1/2)

Step-by-step explanation:

Look for each point on the coordinate graph.

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Which pair of terms can be used to represent any two consecutive odd numbers?

lbvjy [14]

Odd integers are 2 apart from each other (in between them is an even number)

x and x+2 is answer

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3 years ago

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What value is added to both sides of the equation x2 − 8x = −10 in order to solve by completing the square?−816−44?

Artyom0805 [142]

Do you see -8x?

Take half of -8 and square it.

So, (-8)/2 = -4.

(-4)^2 = 16

Now add 16 to both sides.

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3 years ago

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Suppose that you have $6000 to invest. Which investment yields the greater return over four years: 8.25% compounded quarterly or

WARRIOR [948]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.0825}{4}\right)^{4\cdot 4}\implies A=6000(1.020625)^{16}\\\\
-------------------------------\\\\$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$6000\\
r=rate\to 8.3\%\to \frac{8.3}{100}\to &0.083\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semiannually, thus two}
\end{array}\to &2\\
t=years\to &4
\end{cases}
\\\\\\
A=6000\left(1+\frac{0.083}{2}\right)^{2\cdot 4}\implies A=6000(1.0415)^8$

compare them away.

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3 years ago

In a “Fibonacci” sequence of numbers, each term beginning with the third, is the sum of the previous two terms. The first number

Fed [463]

Answer:

8th term=107

Step-by-step explanation:

Here the sequence is following the 'fibonacci's sequence of numbers.....

i.e,Tn=T(n-1) +T(n-2), where n>2 but this sequence is not fibonnaci's number , it's not starting with 0, 1,1,2........

so you cannot apply formula to calculate,you have to find 8th term by simple calculation.....

Like here 3rd term is 9 and 1st term is 2

now 3rd term = 2nd term+1st term (sum of previous two terms)

i.e, 9= 2nd term +2

i.e, 2nd term =7

now, 4th term = 3rd +2nd

= 9+7=16

again, 5th term = 4th +3rd

=16+9=25

again,6th term =5th+4th

=25+16=41

again,7th term=6th+5th

=41+25=66

again,8th term=7th+6th

=66+41=107

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3 years ago

The mean of 20 items is 40 and the mean of

kipiarov [429]

Answer:

At this point just choose a mean thats half of the value

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