Since only the first term has ax for coefficients the GCF cant be -3ax^5.
The GCF would be -3a
Factor -3a out of all the terms:
-3a(2x^7)-3a(-4a^5)-3a(a^4)
Now factor -3a out of the equation for the final answer:
-3a(2x^7-4a^5+a^4)
This will be easier to write, and a lot easier to read, if we temporarily
use another symbol ... say, 'Q' ... to represent ' sin(2x) ' .
Here we go:
Original equation: Q² - 0.5 Q = 0
Factor the left side: Q (Q - 0.5) = 0
This equation is true if either factor is zero:
-- If Q=0, then sin(2x) = 0
2x = 0°, 180°, 360°
x = 0°, 90°, 180°
-- If (Q-0.5) = 0, then Q = 0.5
sin(2x) = 0.5
2x = 30°, 150°
x = 15°, 75°
The whole collection of solutions
between 0° and 360° :
x = 0°, 15°, 75°, 90°, 180° .
A and b.
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Answer:
7 groups can be made each with five people :)
Answer:
x = 0.125
Step-by-step explanation:
Given:
log₃(x²) = 1
Now,
From the properties of log
logₓ (z)= 
(where the base of the log is equal for both numerator and the denominator)
also,
log(xⁿ) = n × log(x)
thus,
using the above properties, we can deduce the results as:
logₓ(y) = n is equivalent to y = xⁿ
therefore,
the given equation can be deduced as:
log₃(x²) = 1
or
2log₃(x) = 1
or
log₃(x) = 0.5
into,
x = 0.5³
or
x = 0.125
