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2 years ago

Define the term peripheralsplz answer right answer mark the brainlist

Mathematics

1 answer:

Alekssandra [29.7K]2 years ago

4 0

Answer:

Peripherals are devices that are not the computer's centre structure of memory and processing. Surface devices include input hardware, output hardware and storage devices.

Step-by-step explanation:

Hope this helps you :)

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question is ,four children saved £29 to go on a coach. They each saved the same amount. How much did each saved

Andreas93 [3]

If they saved £29 all together, and if each of them saved the same amount,
then each saved £29/4 = £7.25 or £7 and 25p.

(Before decimalization in 1971, £7.25 would have been £7 and 5s .)

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3 years ago

Read 2 more answers

Rectangle rhombus square isosceles trapezoid

timofeeve [1]

Answer:

Rhombus

Step-by-step explanation:

It does not have congruent diagonals

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3 years ago

$1000 invested with compound interest at a rate of 15% per year for 9 years.

ivolga24 [154]

Answer:

The Final Investment Value is $\$3,517.88$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=9\ years\\ P=\$1,000\\ r=0.15\\n=1$

substitute in the formula above

$A=1,000(1+\frac{0.15}{1})^{1*9}$

$A=\$3,517.88$

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3 years ago

Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

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3 years ago

Which number when added to 45 results in a sum of O?

sesenic [268]

The number is -45 (negative 45)

5 0

3 years ago

Read 2 more answers

Define the term peripheralsplz answer right answer mark the brainlist ​

Define the term peripheralsplz answer right answer mark the brainlist