Ask question

Ask question

All categories

3 years ago

6

How do you solve this please help

1 answer:

dybincka [34]3 years ago

6 0

Since the triangles are congruent the angles given are the same. If we know triangles have 180 degrees total within their angles then 44 + 55 - 180 = 81 degrees. Z=81

You might be interested in

If using the method of completing the square to solve the quadratic equation x^2-13x+14=0, which number would have to be added t

nevsk [136]

Answer:

169/4

Step-by-step explanation:

Take the coefficient of the x term. Here it's -13. Now halve that, obtaining -13/2. Finally, square this result. We get 169/4. This is the desired number.

x^2 - 13x + 169/4 - 169/4 + 14 = 0

7 0

2 years ago

True or False<br> 1. 25190 2510 = 251000

Elenna [48]

Answer:

False

Step-by-step explanation:

That is not true

4 0

3 years ago

Read 2 more answers

Two solids cones geometrically similar and the height of one cone is 1 1/2 times that of the other. Given that the height of the

Nitella [24]

I didnt bring my calculator

6 0

2 years ago

Dwayne has a wrench set with the socket sizes of 1, 1/2, 1/4, 1/8, 1/16 what would the next size be?

lukranit [14]

Notice that the denominator is a multiplied by 2 for each fraction.

1/1•2 = 1/2

1 /2•2 = 1/4

1/4•2 = 1/8

1/8•2 = 1/16

1/16•2 =1/32

The next size is 1/32.

8 0

2 years ago

Show that if A is invertible, then det Upper A Superscript negative 1det A−1equals=StartFraction 1 Over det Upper A EndFraction

netineya [11]

Answer:

Therefore

$det(A)*det(A^{-1}) = 1$ and $det(A^{-1}) = 1/det(A)$

Step-by-step explanation:

Remember that if

$I$ = Identity Matrix

then $det(I)=1$ .

Also remember that for any invertible matrix

$A*A^{-1} = I =$ Identity Matrix.

Therefore

$det(A*A^{-1}) = det(A)*det(A^{-1}) = det(I) = 1$

Therefore

$det(A)*det(A^{-1}) = 1$ and $det(A^{-1}) = 1/det(A)$

7 0

3 years ago