Answer:
1.08 x 10²⁵molecules
Explanation:
From the mole concept we know that ;
1 mole of any substance contains 6.02 x 10²³ molecules
This number is the Avogadro's number.
So;
18 mole of CH will contain:
Number of molecules of CH = 18 x 6.02 x 10²³ = 1.08 x 10²⁵molecules
The number of molecules is therefore 1.08 x 10²⁵molecules
Answer:
Explanation:
The atomic radius of elements are used to estimate the sizes of elements. The atomic radius is taken as half of the inter-nuclear distance between two covalently bonded atoms of non-metallic elements or half of the distance between two nuclei in the solid state of metals.
To solve this problem we will obtain the atomic radius values of the given elements from a standard atomic radius table;
Si 111 pm
P 98 pm
Cl 79 pm
S 87pm
pm = picometer
We see that chlorine has the least atomic radius
The true statements are;
<h3>What is a redox reaction?</h3>
We define a redox reaction as one in which a specie is oxidized and another is reduced.
Now;
Eo cell = cell potential = -0.13 V - (+0.34 V) = -0.47 V
n =number of moles of electrons = 2 mole of electrons
K = equilibrium constant
ΔG = change in free energy
Eo cell = 0.0592/n log K
-0.47 = 0.0592/2 log K
log K = -0.47 * 2/0.0592
K = 1.3 * 10^-16
ΔG = -nFEo cell
ΔG = -(2 * 96500 * -0.47)
ΔG = 90.7kJ
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Answer:
0.6 Ω
Explanation:
From the question given above, the following data were obtained:
Voltage (V) = 12 V
Current (I) = 20 A
Resistance (R) =?
From Ohm's law,
V = IR
Where:
V => is the voltage
I => is the current
R => R is the resistance
With the above formula, we can obtain the resistance as follow:
Voltage (V) = 12 V
Current (I) = 20 A
Resistance (R) =?
V = IR
12 = 20 × R
Divide both side by 20
R = 12 / 20
R = 0.6 Ω
Thus the resistance is 0.6 Ω
Answer:
34 gram of FeO produced 8 gram of oxygen.
Explanation:
Given data:
Mass of FeO = 34 g
Mass of oxygen = ?
Solution;
Chemical equation:
2FeO → 2Fe + O₂
Number of moles of FeO:
Number of moles = mass/ molar mass
Number of moles = 34 g /71.8 g/mol
Number of moles = 0.5 mol
Now we will compare the moles of FeO with oxygen:
FeO : O₂
2 : 1
0.5 : 1/2 × 0.5 = 0.25
Mass of oxygen:
Mass = number of moles × molar mass
Mass = 0.25 mol × 32 g/mol
Mass = 8 g
So 34 gram of FeO produced 8 gram of oxygen.