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3 years ago

Which best compares the roles of nitrogen-fixing bacteria and certain decomposers in the nitrogen cycle?

Chemistry

2 answers:

Novosadov [1.4K]3 years ago

6 0

Answer:

The bacteria convert free nitrogen into nitrogen-containing compounds, while the decomposers convert nitrogen-containing compounds into free nitrogen.

Explanation:

Nitrogen is an essential element for all living organisms. It is required for synthesis protein and nucleic acids and other nitrogenous compounds. Some nitrogen fixing organisms such as Rhizobium, fixes atmospheric nitrogen (N₂) into usable forms such as nitrate (NO₃⁻) or ammonium (NH₄⁺ ) in the soil. The plants take up (NO₃⁻) and (NH₄⁺ )by absorption from the soil by their roots and make protein and nucleic acids. Animals take up nitrogen by eating plants. On death of a plant or animal and the nitrogenous waste produced by animals, decomposers such as bacteria and fungi convert this organic nitrogen into ammonium (NH4⁺) and later into NO₂⁻ and NO₃⁻. Denitrifying bacteria change NO₃⁻ into free nitrogen (N₂).

JulsSmile [24]3 years ago

4 0

Answer: B

Explanation:

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An analytical chemist is titrating of a solution of propionic acid with a solution of 224.9 ml of a 0.6100M solution of propioni

Svetllana [295]

Answer: The pH of acid solution is 4.58

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

For KOH:

Molarity of KOH solution = 1.1000 M

Volume of solution = 41.04 mL

Putting values in equation 1, we get:

$1.1000M=\frac{\text{Moles of KOH}\times 1000}{41.04}\\\\\text{Moles of KOH}=\frac{1.1000\times 41.04}{1000}=0.04514mol$

For propanoic acid:

Molarity of propanoic acid solution = 0.6100 M

Volume of solution = 224.9 mL

Putting values in equation 1, we get:

$0.6100M=\frac{\text{Moles of propanoic acid}\times 1000}{224.9}\\\\\text{Moles of propanoic acid}=\frac{0.6100\times 224.9}{1000}=0.1372mol$

The chemical reaction for propanoic acid and KOH follows the equation:

$C_2H_5COOH+KOH\rightarrow C_2H_5COOK+H_2O$

Initial: 0.1372 0.04514

Final: 0.09206 - 0.04514

Total volume of solution = [224.9 + 41.04] mL = 265.94 mL = 0.26594 L (Conversion factor: 1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{salt}]}{[acid]})$

$pH=pK_a+\log(\frac{[C_2H_5COOK]}{[C_2H_5COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of propanoic acid = 4.89

$[C_2H_5COOK]=\frac{0.04514}{0.26594}$

$[C_2H_5COOH]=\frac{0.09206}{0.26594}$

pH = ?

Putting values in above equation, we get:

$pH=4.89+\log(\frac{(0.04514/0.26594)}{(0.09206/0.26594)})\\\\pH=4.58$

Hence, the pH of acid solution is 4.58

7 0

4 years ago

Can an ion be either positive or negative? True or False

vekshin1

Answer:

True

Explanation:

3 0

3 years ago

A pound of margarine costs $1.39. What is the cost of a kilogram of margarine

den301095 [7]

Answer:

3.064 $

Solution:

First of all we will find the number of pounds contained by one Kg. Therefore, it is found that,

1 Kilogram = 2.20462 Pounds

Hence, as given,

1 Pound of Margarine costs = 1.39 Dollars

So,

2.20462 Pounds Margarine will cost = X Dollars

Solving for X,

X = (2.20462 Pounds × 1.39 Dollars) ÷ 1 Pound

X = 3.064 Dollars

8 0

3 years ago

Helllppppppppp Don’t Guess

ruslelena [56]

Answer:

C. Lithium

Explanation:

I Goo gled it and I think that's right.

3 0

3 years ago

A chemical reaction produces 3.81g potassium chloride (KCl). How many formula units of potassium chloride are there? *Find Molar

Aleks04 [339]

Answer:

The number of formula units in 3.81 g of potassium chloride (KCl) is approximately 3.08 × 10²²

Explanation:

The given parameters is as follows;

The mass of potassium chloride produced in the chemical reaction (KCl) = 3.81 g

The required information = The number of formula units of potassium chloride (KCl)

The Molar Mass of KCl = 74.5513 g/mol

$The \ number \ of \ moles \ of \ a \ substance, n = \dfrac{The \ mass \ of \ the substance}{The \ Molar \ Mass \ of \ the \ substance}$

Therefore, we have;

$The \ number \ of \ moles \ of \ KCl= \dfrac{3.81 \ g}{74.5513 \ g/mol} \approx 0.051106 \ moles$

1 mole of a substance, contains Avogadro's number (6.022 × 10²³) of formula units

Therefore;

0.051106 moles of KCl contains 0.051106 × 6.022 × 10²³ ≈ 3.077588 × 10²² formula units

From which we have, the number of formula units in 3.81 g of potassium chloride (KCl) ≈ 3.08 × 10²² formula units.

8 0

3 years ago