Well i do think they're the same.
Answer:
1.<em>C</em><em>.</em><em>Keeps</em><em> </em><em>blood</em><em> </em><em>sugar</em><em> </em><em>low</em>
Explanation:
i just know number 1 am nt sure of number 2
The IUPAC names of the organic compounds would be as follows:
1. Methanol or 1-Methanol
2. Propan-2-ol or 2-Propanol
3. 2-MethylButane
4. 1-Hexanol
5. 1-Heptanol
<h3>Naming organic compounds</h3>
In the naming of organic compounds, some fundamental rules come into practice. Some of these rules include:
- The longest carbon chain, otherwise known as the parent chain, is considered.
- The substituents must be identified
- The parent chain should be named such that the substituents are located on the lowest-numbered carbons. Repeated substituents are named accordingly.
- Different substituents are named alphabetically and substituents with lower alphabets are considered for the lowest-numbered carbons.
Following these rules and more, the name of the organic compounds whose structures are shown in the image would be as follows:
- Methanol or 1-Methanol
- Propan-2-ol or 2-Propanol
- 2-MethylButane
- 1-Hexanol
- 1-Heptanol
More on IUPAC naming can be found here: brainly.com/question/16631447
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Answer:
A catalyst decreases the activation energy of a reaction.
Explanation:
A catalyst allows a reaction to go through a new pathway that has a lower activation energy. Therefore, it will recquire less energy to reach the transition state (activated complex) which increases the rate of the reaction. This is the reason why adding a catalyst makes a reaction faster.
The figure attached shows the graphical representation of the effect of a catalyst on the activation energy.
