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Stella [2.4K]
2 years ago
12

Ken wants to install a row of ceramic tiles on a wall that is 21 3/8 inches wide. Each tile is 4 1/2 inches wide. What fraction

of a tile must he install at the end of the row to totally fill the space?
Mathematics
1 answer:
pentagon [3]2 years ago
6 0

Answer: 1/4

Step-by-step explanation:

He needs 4 3/4 whole tiles, you could round it to 5 whole tiles. He needed 4 3/4 whole tiles. To completely fill in all the spaces on the wall evenly, it needs to be 5 even, while, tiles. To fill in the empty space, you must subtract 5 and 4 3/4, which explains why Part A says “How many whole tiles does he need” and the answer “4 3/4” So, Subtraction: 5- 4 3/4 = 1/4!

Your welcome :)

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Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

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Answer: $9.26

Step-by-step explanation:

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= 9.90 * (1 + 8.5%)

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Step-by-step explanation:

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The most basic and common reason to use parentheses, brackets, and braces is to control the order of operations.

<h3>What are parentheses?</h3>

In mathematics, parenthesis is used to arrange numbers in the sequence of operations, clarify numbers, and denote multiplication.

Suppose you have an expression as:-

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In this case, you would calculate 5 minus 2 first (parentheses), then multiply by 8 (brackets), then complete the part inside the curly braces, and finally multiply by 6.

Therefore the most basic and common reason to use parentheses, brackets, and braces is to control the order of operations.

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