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TiliK225 [7]
2 years ago
10

(a^-3bc^0)^-2/(ab^3c^4)^5

Mathematics
1 answer:
goldenfox [79]2 years ago
7 0
6b6
——- (Hope this helps)
ac2
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What is the probability of choosing a burrito with cheese and a taco or a wrap with salsa?
neonofarm [45]
7:2
Step-by-step explanation:
Step one is to think about how often tacos are made. Tacos are made often. Now think about how often Wraps are made, not very often. After some research, the ratio is 7 burritos to 2 wraps. This would make the answer 7:2. Unfortunately tacos are more loved than Wraps.
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What is the square root of 18457
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135.9 rounded to the nearest tenth
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3 years ago
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A soup can will have a radius of 4 cm and a
DENIUS [597]

Answer:

<h3>            It's about 365 cm²</h3>

Step-by-step explanation:

2×πr² + 2πr×h =

= 2×π×4² + 2π×4×10.5 =

= 32π + 84π =

= 116π ≈

≈ 364.42 cm²

5 0
2 years ago
Find the area of the figure.<br><br> plz i give brainliest.
Sonja [21]

Answer:

23.5 inches^2

Step-by-step explanation:

Area of triangle = 1/2 * base * height

area = 1/2 * (5+2) * (5+4)

area = 31.5 in^2

Area of rectangle = length * breadth

area = 4 * 2

area = 8 in^2

Area of figure = area of triangle - area of rectangle

area = 31.5 - 8

area =23.5 in^2

6 0
2 years ago
MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0
1 year ago
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