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3 years ago

(a^-3bc^0)^-2/(ab^3c^4)^5

Mathematics

1 answer:

goldenfox [79]3 years ago

7 0

6b6
——- (Hope this helps)
ac2

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Each meat loaf use 3/4lb of meat how much for 8 loaves

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3 years ago

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Someone please help me with this lol… have no idea what I’m doing

Sholpan [36]

Given:

$\cos \theta =\dfrac{3}{5}$

$\sin \theta$

To find:

The quadrant of the terminal side of $\theta$ and find the value of $\sin\theta$ .

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

$\cos \theta =\dfrac{3}{5}$

$\sin \theta$

Here cos is positive and sine is negative. So, $\theta$ must be lies in Quadrant IV.

We know that,

$\sin^2\theta +\cos^2\theta =1$

$\sin^2\theta=1-\cos^2\theta$

$\sin \theta=\pm \sqrt{1-\cos^2\theta}$

It is only negative because $\theta$ lies in Quadrant IV. So,

$\sin \theta=-\sqrt{1-\cos^2\theta}$

After substituting $\cos \theta =\dfrac{3}{5}$ , we get

$\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}$

$\sin \theta=-\sqrt{1-\dfrac{9}{25}}$

$\sin \theta=-\sqrt{\dfrac{25-9}{25}}$

$\sin \theta=-\sqrt{\dfrac{16}{25}}$

$\sin \theta=-\dfrac{4}{5}$

Therefore, the correct option is B.

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3 years ago

Please Answer all if you do I give brainly

Lera25 [3.4K]

Answer:

Squares:

1 is 12.4in

6.2 x 6.2 = 12.4

2 is 21 in

5 1/2 x 4 = 21

Triangles:

1 is 48 in

16+16+16=48

2 is 21 in

$A = \frac{h\x_{b} }{2} = \frac{7 * 6}{2} = 21$

hoped that helped:P

Step-by-step explanation:

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2 years ago