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TiliK225 [7]
3 years ago
10

(a^-3bc^0)^-2/(ab^3c^4)^5

Mathematics
1 answer:
goldenfox [79]3 years ago
7 0
6b6
——- (Hope this helps)
ac2
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5(3 – x) + 1 = 3(x+4)
Yuri [45]

Step-by-step explanation:

<h3><u>✞︎</u><u>G</u><u>i</u><u>v</u><u>e</u><u>n</u></h3>

5(3-x)+1=3(x+4)

<h3><u>✞︎</u><u>T</u><u>o</u><u> </u><u>F</u><u>i</u><u>n</u><u>d</u></h3>

<u>S</u><u>o</u><u>l</u><u>v</u><u>e</u><u> </u><u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u>

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\tt\large\underline{15-5x+1=3x+12}

\large{✰} \bf \underline\color{purple}{16-5x=3x+12}

\tt\large\underline{\longmapsto16-12-3x+5x}

\tt\large\underline{\longmapsto4-8x}

\tt\large\underline{\longmapsto8x=4}

X=\longmapsto\sf \dfrac{\cancel{4}}{\cancel{8}}

\tt\large\underline{\longmapsto \:  \:  \:  \: x =  \frac{1}{2} }

3 0
2 years ago
Use addition or substitution to find the value of y for this set of equations. 4x + 13y = 40 4x + 3y = -40
Aliun [14]
4x + 13y = 40
4x + 3y = -40

multiply second equation by -1

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put y in either original equation

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4x + 24 = -40

subtract 24 from both sides

4x = 64

x=16
y=8
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