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Afina-wow [57]
3 years ago
15

I don’t understand 2(2a-7b) do we put it as 4a-18b or 4a-18

Mathematics
1 answer:
Gwar [14]3 years ago
7 0

Answer:

2(2a-7b) = 4a-14b

Step-by-step explanation:

You have to multiply both the numbers inside brackets (2a,7b) with 2 .....

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What point(s) are 100units away from point -1? Can you pls respond quickly!
Inessa05 [86]

Answer:

Look below.

Step-by-step explanation:

FYI: Im a bit confused on what this question is asking but I am responding based on what I believe the question is asking.

The point 100 spaces to the left of -1 would be (-101,0) and the point 100 spaces to the left of -1 would be (100,0).

The point(s) 100 spaces to the left of -1 would be (- infinity, -1) and the point(s) 100 spaces to the right would be (-1, infinity).

5 0
3 years ago
Mila and Ava play a number game. Mila gives Ava a number and she does three computations:
Lady bird [3.3K]

Answer:

Step-by-step explanation:

(x-5)2+8 = 92

2x-10+8 = 92

2x = 94

x = 47

7 0
3 years ago
Read 2 more answers
6. NO CALCULATOR (except for checking) [VIPP #5] Solve the linear equation. Write solutions in set notation or in sentence form.
GrogVix [38]

Answer:

X_2

Step-by-step explanation:

X_2/5+2X+1/2= 12x_1/10

6 0
3 years ago
Find the area and perimeter.<br> The area is ... and the perimeter is ...
Schach [20]

Answer:

Area: 6a^2

Perimeter: 12a^2

Step-by-step explanation:

To find the area of a triangle, use the formula A=1/2 b*h. The base is 3a^2 and the height is 4a^2.

A= 1/2 (3a^2)(4a^2)

A = 1/2 (12a^4)

A = 6a^4

To find the perimeter of the triangle, add each of the sides of the triangle. The third side, the hypotenuse, can be found using Pythagorean theorem.

a^2+b^2=c^2\\(3a^2)^2+(4a^2)^2 = c^2\\(9a^4)+(16a^4)=c^2\\25a^4=c^2\\5a^2=c

Now add each of the sides: 3a^2 + 4a^2 +5a^2 = 12a^2

7 0
4 years ago
Give an example of a function f : N → N that is surjective but not injective. You must explain why your example is surjective an
Helen [10]

Answer:

Consider f: N → N defined by f(0)=0 and f(n)=n-1 for all n>0.

Step-by-step explanation:

First we will prove that f is surjective. Let y∈N be any natural number. Define x as the number x=y+1. Then x∈N, and f(x)=x-1=(y+1)-1=y.  We conclude that f is surjective.

However, f is not injective. Take x1=0 and x2=1. Then x1≠x2 but f(x1)=0 and f(x2)=x2-1=1-1=0. We have shown that there are two natural numbers x1,x2 such that x1≠x2 but f(x1)=f(x2), that is, f is not injective.

Note:

If 0∉N in your definition of natural numbers, the same reasoning works with the function f: N → N defined by f(1)=1 and f(n)=n-1 for all n>1. The only difference is that you consider x1=1, x2=2 for the injectivity.

7 0
3 years ago
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