38.9
..........
Bcz 6 >5
:)
We can find a formula for nth term of the given sequence as follows:
1, 5, 12, 22, 35
The 1st differences between terms:
4, 7, 10, 13
The 2nd differences :
3, 3, 3
Since it takes two rounds of differences to arrive at a constant difference between terms, the nth term will be a 2nd degree polynomial of the form:
, where c is a constant. The coefficients a, b, and the constant c can be found.
We can form the following 3 equations with 3 unknowns a, b, c:
![1 = a\cdot1^2 + b\cdot1 + c\\5 = \cdot2^2 + b\cdot2 + c\\12 = a\cdot3^2 + b\cdot3 + c](https://tex.z-dn.net/?f=1%20%3D%20a%5Ccdot1%5E2%20%2B%20b%5Ccdot1%20%2B%20c%5C%5C5%20%3D%20%5Ccdot2%5E2%20%2B%20b%5Ccdot2%20%2B%20c%5C%5C12%20%3D%20a%5Ccdot3%5E2%20%2B%20b%5Ccdot3%20%2B%20c)
Solving for a, b, c, we get:
a = 3/2, b = -1/2, c = 0
Therefore, the nth term of the given sequence is:
![\boxed{ a_n = \dfrac{3}{2}n^2- \dfrac{1}{2} n}](https://tex.z-dn.net/?f=%5Cboxed%7B%20a_n%20%3D%20%5Cdfrac%7B3%7D%7B2%7Dn%5E2-%20%5Cdfrac%7B1%7D%7B2%7D%20n%7D)
Answer:
H. 2
Step-by-step explanation:
√(1 − cos² x) / sin x + √(1 − sin² x) / cos x
Use Pythagorean identity.
sin² x + cos² x = 1
So:
1 − cos² x = sin² x
and
1 − sin² x = cos² x
Substitute:
√(sin² x) / sin x + √(cos² x) / cos x
sin x / sin x + cos x / cos x
1 + 1
2
Answer:
<u>Option A</u>
Step-by-step explanation:
To reflect line segment BC over line m, BB' will be perpendicular to the line m
and line m bisector of BB'.
<u>So, the correct answer is option A</u>
A) Line m is the perpendicular bisector of line segment BB' and the line segment CC'
<u>Option b is wrong</u> , it is impossible for the line B'C' to be perpendicular to line BC. B'C' is the image of BC.
<u>Both option c and d is wrong</u> because the perpendicular distance from b to the line m not equal to the perpendicular distance from c to the line m.