Question

If 3.00 liters of 2M HCl neutralizes 1.00 liter of NaOH, what is the molarity of the NaOH?

Answer 1

Answer:

$M_{base}=6M$

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize this is a question about titration, which base solved by knowing that the HCl reacts with the NaOH in a 1:1 mole ratio, and therefore, we can write the following:

$M_{acid}V_{acid}=M_{base}V_{base}$

Thus, we solve for the molarity of the base, NaOH, as shown below:

$M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} \\\\M_{base}=\frac{3L*2M}{1.00L}\\\\M_{base}=6M$

Regards!