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Anna35 [415]
3 years ago
9

If 3.00 liters of 2M HCl neutralizes 1.00 liter of NaOH, what is the molarity of the NaOH?

Chemistry
1 answer:
PilotLPTM [1.2K]3 years ago
7 0

Answer:

M_{base}=6M

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize this is a question about titration, which base solved by knowing that the HCl reacts with the NaOH in a 1:1 mole ratio, and therefore, we can write the following:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the molarity of the base, NaOH, as shown below:

M_{base}=\frac{M_{acid}V_{acid}}{V_{base}} \\\\M_{base}=\frac{3L*2M}{1.00L}\\\\M_{base}=6M

Regards!

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