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IRINA_888 [86]
3 years ago
5

Use the chart to determine which pair of atoms has the greatest difference in electronegativity.

Chemistry
2 answers:
Alekssandra [29.7K]3 years ago
5 0
Here, most electronegative element = Fluorine (4)
Least electronegative = Potassium (0.82)

In short, Fluorine(F) & Potassium (K) have greatest difference in electronegativity of about 3.18

Hope this helps!
PilotLPTM [1.2K]3 years ago
3 0

The answer is: the greatest difference in electronegativity have K and F.

Electronegativity (χ) is a property that describes the tendency of an atom to attract a shared pair of electrons.  

Atoms with higher electronegativity attracts more electrons towards it, electrons are closer to that atom.  

For example fluorine has electronegativity χ = 4 and potassium χ = 0.82, fluorine attracts electron and it has negative charge and sodium has positive charge.  

Δχ(K-F) = 4 - 0.82.

Δχ(K-F) = 3.18; electronegativity difference between potassium and fluorine.

When the electronegativity difference is greater, the bond polarity is increasing.  

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Now we will calculate the number of moles of ammonia:

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Now we will compare the moles of ammonia with oxygen from balance chemical equation.

                        NH₃              :                O₂

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                          1.1                :              5/4×1.1 = 1.375 mol

Mass of oxygen needed:

Mass = number of moles × molar mass

Mass = 1.375 mol × 32 g/mol

Mass = 44 g

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