Answer:
v = 21 m / s
Explanation:
We can solve this exercise with the kinematics equations, let's start by finding the acceleration of the train with the initial data
v = v₀ + a t
the initial speed is the speed within the city 6 m / s, the final speed is v = 11 m / s and the time is t = 8 s
a = (v-v₀) / t
a = (11 - 6) / 8
a = 0.625 m / s²
when it leaves the city with speed vo = 11 m / s it accelerates for t = 16 s
v = v₀ + a t
v = 11 + 0.625 16
v = 21 m / s
The sign of the charged particle is positively charged.
<h3>What is potential difference?</h3>
- When a single charge is transported in an electric field, work is done by the potential difference (also known as electrical potential).
- There is potential energy stored in this charge that could flow when work is done on it.
- Voltage is the possibility of a single charge flowing. The need to flow increases with voltage.
- Here, voltage can be the potential differences.
The potential difference between the 2 points determines the movement of that particle. An electron moves from lower to higher potential which is negatively charged, and a positively charged particle moves from higher to lower potential.
Now, since the particle is moving from a point A having 160 v potential to point B having 100 v potential that is it is moving from higher potential to a lower potential therefore the particle will be a positively charged one.
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<span>Hitting can be broken down into three segments; SEE, REACT, SWING. You watch the ball in the pitcher's hand during the windup and you watch the ball leave the pitcher's hand when it is thrown and you watch the spin of the ball as it comes towards the plate. That is SEE. You determine what the pitch is (fastball, curveball, etc.), you determine where the ball is going to go and you determine whether it is headed towards an area that you think you can get good wood on it. That is REACT. You swing if you like the pitch or don't swing if you don't like the pitch. That is SWING. It doesn't make any difference whether you are playing with a tennis ball or a golf ball or a baseball. The theory and mechanics are the same. So, to answer your question I would say the more you practice the better you will be, regardless of the type of ball you use to practice with.</span>
Answer:
K.E is 2.25 J
Explanation:
Data :
Mass = m = 0.5 kg
Velocity = v = 3 m/s
Formula for K.E
K.E = 1/2mv²
Put values
K.E = 1/2(0.5)(3)² = 2.25 J
When a ball is thrown up by doing work, the velocity of the ball will be 2.6 m/s.
<h3>What is Work energy theorem?</h3>
It states that the Work done in moving a body is equal to the change in kinetic energy of the body
Kinetic energy = 1/2 mv²
Given is a ball of mass m = 0.750 kg and the work done on ball W = 2.50 J
The ball is initially at rest. So, initial velocity is zero. Then, change in kinetic energy will be
W= ΔK.E = K.Ef - K.Ei
According to work energy theorem, work done is
W = 2.5J = 1/2 x 0.750 x (v)² -0
v =2.6 m/s
Thus, the velocity of the ball is 2.6 m/s
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