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LenKa [72]
3 years ago
14

Which of the following is NOT a true statement about error in hypothesis​ testing?Choose the correct answer below.A.The symbol a

lpharepresents the probability of a type I error.B.A type I error is making the mistake of rejecting the null hypothesis when it is actually true.C.A type II error is making the mistake of failing to reject the null hypothesis when it is actually false.D.A type I error is making the mistake of rejecting the null hypothesis when it is actually false.
Physics
1 answer:
Marizza181 [45]3 years ago
8 0

Answer:

Option D

A type I error is making the mistake of rejecting the null hypothesis when it is actually false.

Explanation:

Error type I is usually represented by alpha symbol and type I error entail making a mistake of rejecting the  null hypothesis when it's actually true. Type II error on the other side involves making a mistake of failing to reject null hypothesis when it is actually false. The statement in option D is false because it contradicts the definition of type I error above hence the only false statement in relation to hypothesis testing is option D, A type I error is making the mistake of rejecting the null hypothesis when it is actually false.

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Find the magnitude of the resultant force and the angle it makes with the positive x-axis. (Let |a| = 22 lb and |b| = 16 lb. Rou
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Incomplete question as the angle between the force is not given I assumed angle of 55°.The complete question is here

Two forces, a vertical force of 22 lb and another of 16 lb, act on the same object. The angle between these forces is 55°. Find the magnitude and direction angle from the positive x-axis of the resultant force that acts on the object. (Round to one decimal places.)  

Answer:

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Explanation:

Given data

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To find

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(ii)Angle α

Solution

First we need to represent the forces in vector form

\sqrt{x} F_{1}=22j\\ F_{2}=u+v\\F_{2}=16sin(55)i+16cos(55)j\\F_{2}=16(0.82)i+16(0.5735)j\\F_{2}=13.12i+9.176j

Total Force

F=F_{1}+F_{2}\\ F_{2}=22j+13.12i+9.176j\\F_{2}=13.12i+31.176j

The Resultant Force is given as

|F|=\sqrt{x^{2} +y^{2} }\\|F|=\sqrt{(13.12)^{2} +(31.176)^{2} }\\ |F|=33.8lb

For(ii) angle

We can find the angle bu using tanα=y/x

So

tan\alpha =\frac{31.176}{13.12}\\ \alpha =tan^{-1} (\frac{31.176}{13.12})\\\alpha =67.2^{o}

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