1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ryzh [129]
3 years ago
9

What would the force be on a 14.5 kg object that was accelerating 2.7 m/s^2

Physics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

<h2>39.15 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 14.5 × 2.7

We have the final answer as

<h3>39.15 N</h3>

Hope this helps you

You might be interested in
PLEASE HELPPPP ❗️❗️❗️
mojhsa [17]

Answer:

Explanation:

There are 3 main forces at work here, gravity, normal and friction. The gravity pulls the car straight down and is what keeps the car on the ground. Normal force is straight up from the points where the car is touching, so since the wheels are the only parts of the car touching the street, this is where all the normal force is. Friction force opposes any and all motion, the car wants to slide down the hill and would slide down the hill if there was no friction, so the friction force is in the opposite direction of the cars intended motion.

Download pdf
8 0
3 years ago
Hi can you help me with this please?
bagirrra123 [75]

Answer:

4s

Explanation:

My assumption would be 4s since 25 going into 100 would be 4? hope that helped..

5 0
3 years ago
1 point
avanturin [10]

Answer:

D. The water on her skin evaporates quickly and cools her skin.

Explanation:

7 0
4 years ago
A golfer hits a shot to a green that is elevated 3.20 m above the point where the ball is struck. The ball leaves the club at a
dem82 [27]

Answer:

16.17 m/s

Explanation:

h = 3.2 m

u = 18.1 m/s

Angle of projection, θ = 49°

Let H be the maximum height reached by the ball.

The formula for the maximum height is given by

H=\frac{u^{2}Sin^{2}\theta }{2g}

H=\frac{18.1^{2}\times Sin^{2}49 }{2\times 9.8}=9.52 m

The vertical distance fall down by the ball, h'  H - h = 9.52 - 3.2 = 6.32 m

Let v be the velocity of ball with which it strikes the ground.

Use third equation of motion for vertical direction

v_{y}^{2}=u_{y}^{2}+2gh'

here, uy = 0

So,

v_{y}^{2}=2\times 9.8 \times 6.32

vy = 11.13 m/s

vx = u Cos 49 = 18.1 x 0.656 = 11.87 m/s

The resultant velocity is given by

v=\sqrt{v_{x}^{2}+v_{y}^{2}}

v=\sqrt{11.87^{2}+11.13^{2}}

v = 16.27 m/s

7 0
4 years ago
Name two possible ways in wivh fossils can be dated and define them <br>​
Vikentia [17]

Answer:

There are two main methods determining a fossils age, relative dating and absolute dating. Relative dating is used to determine a fossils approximate age by comparing it to similar rocks and fossils of known ages.

Mark me with a crown

6 0
3 years ago
Read 2 more answers
Other questions:
  • A single-slit diffraction pattern is formed by monochromatic electromagnetic radiation from a distant source passing through a s
    13·1 answer
  • Locate the best example of symbolic representation.
    9·1 answer
  • When separated by distance d, identically charged point-like objects A and B exert a force of magnitude F on each other. If you
    14·1 answer
  • How far will 350 j raise a 7 kg mass?
    10·1 answer
  • In a velocity time graph, the slope of the line gives the____.​
    11·1 answer
  • A jogger runs 224 meters eastward, then 156 meters
    11·1 answer
  • Can someone please help me?
    9·2 answers
  • ASAP pls answer I will mark brainiest if right.
    11·1 answer
  • You push on the top edge of a 1.8 m tall solid circular cylinder of iron which is 4.00 cm in diameter. You push with a horizonta
    7·1 answer
  • You and a partner sit on the floor and stretch out a coiled spring to a length of 7.2 meters. You shake the coil so you
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!