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3 years ago

Please help I need these points bro.

Mathematics

1 answer:

fenix001 [56]3 years ago

4 0

Answer:

y= 0.8x

Step-by-step explanation:

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Select the three equations that pass through the points (-4, -16) and (5,2).

dezoksy [38]

Answer:

The equation of the line is $y-2 = 2(x - 5)$ , that passes through points $(-4, -16)\ and\ (5,2)$

Step-by-step explanation:

Given points are $(-4, -16)\ and\ (5,2)$

We need to write the equation of the line that passes through these points

First, we will find slope of this line

$m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{2-(-16)}{5-(-4)}\\\\m=\frac{2+16}{5+4}\\\\m=\frac{18}{9}=2$

So, our slope is $2$ . Now, we will plug the point $(5,2)$ in the equation below.

$(y-y_1)=m(x-x_1)\\y-2=2(x-5)\\$

So, the equation of the line is $y-2 = 2(x - 5)$ .

5 0

3 years ago

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4x-5(3x+10)=126<br><br> what’s the value of X?

nordsb [41]

X= -16 brahhhhh you’re welcome

6 0

3 years ago

Which is the solution to the inequality?

Zinaida [17]

Answer: The Answer is B the second one.

Step-by-step explanation:

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2 years ago

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How many cans will your school need to collect to recycle one ton

natima [27]

1 ton = 2000lbs
2000 = a * 1/25
so we can know that a/25 = 2000 and then 2000* 25 = a and then 50000 = a

so we need 50000 cans

7 0

3 years ago

What is the ratio of the volume of a cube with edge length six inches to the volume of a cube with edge length one foot? Express

gladu [14]

Answer:

The ratio is $\frac{1}{8}$

Step-by-step explanation:

The volume of a cube with edge length a is:

$V = a^{3}$

We have two cubes:

Cube 1: The one with edge length of six inches.

Cubs 2: The one with edge length of one foot.

The ratio is:

$R = \frac{V_{C1}}{V_{C2}}$

In which $V_{C1}$ is the volume of the first cube and $V_{C2}$ is the volume of the second cube.

Volume of the first cube

The edge length is 6 inches, so $a = 6$ .

$V_{C1} = 6^{3} = 216 inches^{3}$

Volume of the second cube

To express the ratio as a common fraction, both volumes must be in the same unit. So we must pass the edge length of the second cube to inches.

The second cube has edge length of one foot. Each foot has twelve inches. So

$V_{C2} = 12^{3} = 1720 inches^{3}$

Ratio:

$R = \frac{V_{C1}}{V_{C2}} = \frac{216}{1720} = \frac{1}{8}$

3 0

3 years ago